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3 years ago

15

A cookie jar contains 2 chocolate chip cookies, 4 peanut butter cookies, and 3 sugar cookies. A child chooses one cookie at rand

om, eats it, and then chooses another cookie to eat. Find the probability that: one cookie is chocolate chip and one cookie is peanut butter

1 answer:

marishachu [46]3 years ago

5 0

Answer:

Peanutbutter 44%

Chocolate chip 22%

Step-by-step explanation:

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What is the quotient of (2x3 – 29x + 13) ÷ (x + 4)?

sleet_krkn [62]

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Answer:

C. 2x^2 -8x +3 +1/(x +4)

Step-by-step explanation:

Synthetic division is useful for finding the quotient. Or, you can use polynomial long division. The result is the same, but synthetic division requires less writing.

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3 years ago

A test of intelligence is given to a subject. The subject scores 110 on the first administration. Six months later, the same sub

Basile [38]

Answer:

True, the scores are not valid.

Step-by-step explanation:

The test supposed to be measuring intelligence. We can assume that the intelligence of most people relatively stable (will not change too much over a short amount of time), and can expect it should go upward with brain growth and education. But the test seems to give a huge decrease from the first and second results. Then the third result is a huge increase that even higher than the first test.

We don't know the true value of the subject, but seeing the huge gap for every repetition we can tell that the test result lacks precision.

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3 years ago

Which problem could be solved by evaluating the expression 7 x (-3)?

Tasya [4]

Answer:

The answer is -21

Step-by-step explanation:

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3 years ago

Read 2 more answers

To help consumers assess the risks they are taking, the Food and Drug Administration (FDA) publishes the amount of nicotine foun

QveST [7]

Answer:

We conclude that the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 31.7 milligrams

Sample mean, $\bar{x}$ = 28.5 milligrams

Sample size, n = 9

Alpha, α = 0.05

Sample standard deviation, s = 2.8 milligrams

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 31.7\text{ milligrams}\\H_A: \mu < 31.7\text{ milligrams}$

We use One-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{28.5 - 31.7}{\frac{2.8}{\sqrt{9}} } = -3.429$

Now, $t_{critical} \text{ at 0.05 level of significance, 8 degree of freedom } = -1.860$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and accept the alternate hypothesis. We conclude that the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.

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Answer:

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Step-by-step explanation:

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