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liberstina [14]
3 years ago
15

Please give me the ans​

Mathematics
1 answer:
maks197457 [2]3 years ago
7 0

Answer:

how to use a c a l c u l a t o r

Step-by-step explanation:

1. g o o g l e

2. add parenthesis if needed

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How to set the answer up
Korolek [52]

Let s and g represents the numbers of suits and gowns produced.

The number of zippers used is 2s+g.

The number of buttons used is 5s+8g.

In order to use all of the available zippers and buttons, we must have ...

  • 2s + g = 171
  • 5s + 8g = 576

Cramer's rule tells you the solution to the system

  • ax +by = c
  • dx +ey = f

Is given by

  • x = (bf-ey)/(bd-ea)
  • y = (cd-fa)/(bd-ea)

Using this rule on the equations for zippers and buttons, we have

... s = (1·576 -8·171)/(1·5 -8·2) = -792/-11 = 72

... g = (171·5 -2·576)/-11 = -297/-11 = 27

72 suits and 27 gowns can be made from available zippers and buttons.

3 0
4 years ago
six times jason collection of books and one third of nathan collection add up to 134 books. one third of jason collection and na
raketka [301]

Answer:

j = 21 and n = 14

Step-by-step explanation:

we have the equations:

6j + n/3 = 134

j/3 + n = 31

54j + 3n = 1206

j + 3n = 93

53j = 1113

j = 21

(21)/3 + n = 31

7 + n = 31

n = 14

6 0
3 years ago
(03.01 LC)<br><br> What is the length of leg y of the right triangle? (1 point)
EastWind [94]

Answer:

<h2>A</h2>

Step-by-step explanation:

The complete question is

What is the length of leg y of the right triangle?

A right triangle with hypotenuse 26 and legs 24 and y

  • 10
  • 14
  • 24
  • 26

We need to use the Pythagorean Theorem, where h=26 and x=24,

h^{2} =x^{2} +y^{2}\\ 26^{2}=24^{2}+y^{2}\\y=\sqrt{26^{2}-24^{2}}\\ y=\sqrt{676-576}\\ y=\sqrt{100}\\ y=10

Therefore, the right answer is A. The length of the missing leg is 10 units.

4 0
3 years ago
What is the reference angle for 295 degrees?
Kay [80]
A reference angle is always between 0-90. so 360-295=65deg.
<span>Hints:  </span>
<span>Quadrant I angle: reference angle is same as given angle. </span>
<span>Quad II: subtract angle from 180 </span>
<span>Quadrant III: subtract 180 from angle </span>
<span>Quad IV: subtract angle from 360.</span>
4 0
3 years ago
Read 2 more answers
Give the following equations determine if the lines are parallel perpendicular or neither
GaryK [48]

In order to determine whether the equations are parallel, perpendicular, or neither, let's simply each equation into a slope-intercept form or basically, solve for y.

Let's start with the first equation.

\frac{6x-5y}{2}=x+1

Cross multiply both sides of the equation.

6x-5y=2(x+1)6x-5y=2x+2

Subtract 6x on both sides of the equation.

6x-5y-6x=2x+2-6x-5y=-4x+2

Divide both sides of the equation by -5.

-\frac{5y}{-5}=\frac{-4x}{-5}+\frac{2}{-5}y=\frac{4}{5}x-\frac{2}{5}

Therefore, the slope of the first equation is 4/5.

Let's now simplify the second equation.

-4y-x=4x+5

Add x on both sides of the equation.

-4y-x+x=4x+5+x-4y=5x+5

Divide both sides of the equation by -4.

\frac{-4y}{-4}=\frac{5x}{-4}+\frac{5}{-4}y=-\frac{5}{4}x-\frac{5}{4}

Therefore, the slope of the second equation is -5/4.

Since the slope of each equation is the negative reciprocal of each other, then the graph of the two equations is perpendicular to each other.

5 0
1 year ago
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