If 24, x, and 6 form the first three terms of an arithmetic sequence
1 answer:
<h3>
Answer: 15</h3>
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Work Shown:
d = common difference
p = first term = 24
q = second term = a+d = 24+d
r = third term = q+d = 24+d+d = 24+2d = 6
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Solve for d
24+2d = 6
2d = 6-24
2d = -18
d = -18/2
d = -9
We add -9 to each term to get the next term. This is the same as subtracting 9 from each term to get the next term.
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First term = 24
Second term = 24-9 = 15
Third term = 15-9 = 6
We get the sequence 24, 15, 6
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