First we need to see in which quadrant 11pi/6 lies And it lies in fourth quadrant. And to find the reference angle in the fourth quadrant, we need to subtract the given angle from 2 pi . For e.g if the angle is 5pi/3, then the reference angle is 2pi - (5pi/3) = pi/3 .
So for the given question, reference angle of 11pi/6 is
And that's the required reference angle .
Answer
P= 2L+2W
P=2(12) +2(7) =38
Step-by-step explanation:
The width of a rectangle is 5 meters less than its length. The area is 84 square meters. Find the dimensions of the rectangle and the perimeter of the rectangle.
First it helps to draw a picture so draw a rectangle
Remember that area of a rectangle =Length times width and the perimeter is P= 2 times the length plus 2 times the width
So A=LW and P=2L+2W
84= area
L=length
W= length -5
L(L-5)=84 distribute the L and you have L2 -5L=84 now subtract 84 from both sides and get L2 �5L-84 next factor to get (L+7)(L-12) next set both to =0 (L+7)=0 (L+12)=0 solve for L
L=-7 and L=12 you can�t have a negative length so -7 is out. So L=12 now plug in to the original area equation
84=LW 84= 12w now divide both sides by 12 to isolate W, this gives you W=7
L=12 and W= 7
For perimeter use 12 for the length and 7 for width Remember that P= 2L+2W
P=2(12) +2(7) =38
Answer:
6m
Step-by-step explanation:
Hope this helps!!!
I don't understand................
she reads 49 pages in one hour.
