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3 years ago

15

FIND THE MEASURE OF EACH MISSING ANGLE HURRY DUE AT 10

1 answer:

max2010maxim [7]3 years ago

5 0

Because of a linear pair then because of vertical angles and because all angles have to be 180 added up

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Please help! this is a final! FUNCTIONS

Gnom [1K]

The zeroes are -1/2 and -2
last option

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3 years ago

What is the volume of the triangular prism prism? <br> 8cm<br> 13cm<br> 3cm

Vika [28.1K]

Answer:

156 cm3

If the length is 8cm and the base is 13cm and the prism height is 3cm

8 0

3 years ago

Jose and Frank made 3 1/5 pounds of pasta. They ate 1 2/5 pounds for dinner. How much was left over?

Lyrx [107]

Hi there,

It is 1 4/5. In decimal it is 1.8. Hope it helps:-)

6 0

3 years ago

How do you factor 5x^2b^2 + 14xb^2 -3b^2

Monica [59]

Answer:

$5b^2(x-0.2)(x+3)$

Step-by-step explanation:

The first thing that I noticed was that all of the terms had a common factor of $b^2$ . You can therefore factor that out first:

$5x^2b^2 + 14xb^2 -3b^2= \\\\b^2(5x^2+14x-3)$

Now, you have a quadratic equation inside the parentheses. Factoring, you find that the roots are -0.2 and 3, meaning that you can further factor this expression to be:

$5b^2(x-0.2)(x+3)$

Hope this helps!

3 0

3 years ago

Given sin(u)= -7/25 and cos(v) = -4/5, what is the exact value of cos(u-v) if both angles are in quadrant 3

solmaris [256]

Given:

$\sin (u)=-\dfrac{7}{25}$

$\cos (v)=-\dfrac{4}{5}$

To find:

The exact value of cos(u-v) if both angles are in quadrant 3.

Solution:

In 3rd quadrant, cos and sin both trigonometric ratios are negative.

We have,

$\sin (u)=-\dfrac{7}{25}$

$\cos (v)=-\dfrac{4}{5}$

Now,

$\cos (u)=-\sqrt{1-\sin^2 (u)}$

$\cos (u)=-\sqrt{1-(-\dfrac{7}{25})^2}$

$\cos (u)=-\sqrt{1-\dfrac{49}{625}}$

$\cos (u)=-\sqrt{\dfrac{625-49}{625}}$

On further simplification, we get

$\cos (u)=-\sqrt{\dfrac{576}{625}}$

$\cos (u)=-\dfrac{24}{25}$

Similarly,

$\sin (v)=-\sqrt{1-\cos^2 (v)}$

$\sin (v)=-\sqrt{1-(-\dfrac{4}{5})^2}$

$\sin (v)=-\sqrt{1-\dfrac{16}{25}}$

$\sin (v)=-\sqrt{\dfrac{25-16}{25}}$

$\sin (v)=-\sqrt{\dfrac{9}{25}}$

$\sin (v)=-\dfrac{3}{5}$

Now,

$\cos (u-v)=\cos u\cos v+\sin u\sin v$

$\cos (u-v)=\left(-\dfrac{24}{25}\right)\left(-\dfrac{4}{5}\right)+\left(-\dfrac{7}{25}\right)\left(-\dfrac{3}{25}\right)$

$\cos (u-v)=\dfrac{96}{625}+\dfrac{21}{625}$

$\cos (u-v)=\dfrac{1 17}{625}$

Therefore, the value of cos (u-v) is 0.1872.

6 0

3 years ago