Answer:
30 m/s
Step-by-step explanation:
Let's say the distance from the first car to the intersection is x, and the distance from the second car to the intersection is y.
The distance between the cars can be found with Pythagorean theorem:
d² = x² + y²
Taking derivative with respect to time:
2d dd/dt = 2x dx/dt + 2y dy/dt
d dd/dt = x dx/dt + y dy/dt
We know that x = 200, dx/dt = -25, y = 150, and dy/dt = -50/3.
To find dd/dt, we still need to find d.
d² = x² + y²
d² = (200)² + (150)²
d = 250
Plugging everything in:
250 dd/dt = (200) (-25) + (150) (-50/3)
dd/dt = -30
The cars are approaching each other at a rate of 30 m/s at that instant.
I really hope this helps. I’m sure the answer is c:)
Answer:
multiply the numbers next to the variables by the given subtitution for the variable so 5 times 14 plus 36 and 6 times 12.5 minus 1 and 4 times 14 plus 50
Step-by-step explanation:
Answer:
y= -x^2+5
Step-by-step explanation:
It normally expontionally goes up, so across the x axis is down so it is negative, and is is all scales up, so the start is 5 up from the origin on the y axis, so it would be y=-x+5
Hope this helped!
Answer:
One ticket equals $169
Step-by-step explanation:
The family buys 4 airline tickets online.
The travel insurance costs $19 per ticket.
The total cost is $752.
A.
An equation that models this problem could be
Basically, we know that the insurance costs $19 which represents an additional costs after the price per ticket, that's why we need to add them. Then, we know that the familiy bought 4 tickes, that's why we multiply by 4, and finally, the total cost must be equal to 752, according to the problem.
B.
To find the price of one ticket, we just need to solve the equation for
Therefore, one ticket costs $169.
