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Maslowich
3 years ago
15

The perimeter of a rectangle is 50 cm and the length is 4 cm longer than the width. Write and solve the system of equations usin

g the substitution method.

Mathematics
1 answer:
laila [671]3 years ago
3 0
I hope this helps you

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Elis [28]

Answer: 12

Step-by-step explanation:

42

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42

6 0
3 years ago
Which lines in the graph have a slope greater than 1 but less than 2?
lapo4ka [179]

Answer:

Lines 3 and 4

Step-by-step explanation:

Let's examine the slope of each of the given lines to have the exact value and be able to answer the question. We use the definition of: slope=\frac{rise}{run}

Line 1: slope=\frac{rise}{run}=\frac{6}{2} = 3

Line 2: slope=\frac{rise}{run}=\frac{6}{3} = 2

Line 3: slope=\frac{rise}{run}=\frac{6}{4} = 1.5

Line 4: slope=\frac{rise}{run}=\frac{6}{5} = 1.2

Line 5: slope=\frac{rise}{run}=\frac{6}{6} = 1

Therefore the lines that have slope strictly greater than 1 and less than 2 are:

Lines 3 and 4

3 0
3 years ago
Read 2 more answers
(ASAP PICTURE ADDED) What is the simplified form of the following expression?
bonufazy [111]

Answer:

option c is correct.

Step-by-step explanation:

7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{16x}\right)-3\left(\sqrt[3]{8x}\right)

WE need to simplify this equation.

Solve the parenthesis of each term.

=7\left\sqrt[3]{2x}\right-3\left\sqrt[3]{16x}\right-3\left\sqrt[3]{8x}\right

Now, We will find factors of the terms inside the square root

factors of 2: 2

factors of 16 : 2x2x2x2

factors of 8: 2x2x2

Putting these values in our equation:=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)

Adding like terms we get:

=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right\\=(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\

(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\can\,\,be \,\, written\,\, as\,\,\\(\sqrt[3] {2x})-6\left(\sqrt[3]{x}\right)

So, option c is correct

5 0
3 years ago
Read 2 more answers
what is the answer to 18 2/5 - 9 13/ 15 andb 28 3/9 - 19 5/6. Plz help her now!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
wel

8 and 8/15 or 128/15 and 8.5

4 0
3 years ago
The length of a rectangle is three feet less than twice its width. If x
d1i1m1o1n [39]
 So if the question says at most 30 sq ft than most likely the > is going to go this way even if it has a line that symbolizes equal or more so that kinda narrows it down to 2 and 4. The L is -3ft x 2 Id say 4. Hope I helped 
5 0
3 years ago
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