1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Iteru [2.4K]
3 years ago
14

There are 500 rabbits in Lancaster on February 1st. If the amount of rabbits triples every month. Write a function that represen

ts the number of rabbits in Lancaster after “m” months. How many rabbits are there in Lancaster on August 1st?
Please explain
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

10,93,500.

Step-by-step explanation:

On first February total number of rabbits were 500.

Now it is given that after each month rabbit population will become triple of initial.

So, after one month rabbits will become 3×500.

After two months they will become 3^{2}×500.

Thus , after m months total number of rabbits will become 3^{m}×500.

Now,

On August 1 , 7 months will get passed from February 1 so putting m = 7 in the equation we get ,

Total number of rabbits = 3^{7}×500 = 10,93,500.

You might be interested in
Select the two binomials that are factors of 81x2 -36
grigory [225]

Answer:

81, and 2

Step-by-step explanation:

Binomials are the two parts of a equation in this case 81 times 2  -36, 81 and 2 would be the binomials because they're the first two parts of the equation.

Other examples:

x - y

x \times y

x + y

x \div y

Hope this helps.

6 0
3 years ago
I needs help please, a step by step answer
trapecia [35]

Answer:

68

Step-by-step explanation:

Pythagorean theorem: a²+b²=c²  a²=32²   b²=60²   c²=hypotenuse²

32²+60²=c²

1024+3600= c²

4624=c²

Now, take the square root of both sides of the equation to find c

\sqrt{4624}=c

68=c

6 0
2 years ago
Read 2 more answers
HELP MEEEEEE PLEASE<3
Mama L [17]

Answer:

3 3/5 miles

Step-by-step explanation:

6 3/4 divided by 1 7/8=

3 3/5

4 0
2 years ago
Read 2 more answers
Find the? inverse, if it? exists, for the given matrix.<br><br> [4 3]<br><br> [3 6]
True [87]

Answer:

Therefore, the inverse of given matrix is

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

Step-by-step explanation:

The inverse of a square matrix A is A^{-1} such that

A A^{-1}=I where I is the identity matrix.

Consider, A = \left[\begin{array}{ccc}4&3\\3&6\end{array}\right]

\mathrm{Matrix\:can\:only\:be\:inverted\:if\:it\:is\:non-singular,\:that\:is:}

\det \begin{pmatrix}4&3 \\3&6\end{pmatrix}\ne 0

\mathrm{Find\:2x2\:matrix\:inverse\:according\:to\:the\:formula}:\quad \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}^{-1}=\frac{1}{\det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}}\begin{pmatrix}d\:&\:-b\:\\ -c\:&\:a\:\end{pmatrix}

=\frac{1}{\det \begin{pmatrix}4&3\\ 3&6\end{pmatrix}}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}

\mathrm{Find\:the\:matrix\:determinant\:according\:to\:formula}:\quad \det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}\:=\:ad-bc

4\cdot \:6-3\cdot \:3=15

=\frac{1}{15}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

Therefore, the inverse of given matrix is

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

4 0
3 years ago
Which of the following statements are true?
Eduardwww [97]

Answer:

B, C

Step-by-step explanation:

Consider all options:

A. The graph of the function f(x)=\dfrac{1}{2}\sqrt[3]{x} is vertically shrunk by a factor \frac{1}{2} the graph of the function f(x)=\sqrt[3]{x}, so the domain and the range of both functions are the same. This option is false.

B.  The graph of the function f(x)=\dfrac{1}{2}\sqrt[3]{x} is vertically shrunk by a factor \frac{1}{2} the graph of the function f(x)=\sqrt[3]{x}, so the domain and the range of both functions are the same. This option is true.

C. The graph of the function f(x)=\dfrac{1}{2}\sqrt[3]{(x-2)} is translated 2 units to the right and vertically shrunk by a factor \frac{1}{2} the graph of the function f(x)=\sqrt[3]{x}, so their graphs are similar except the first graph is shifted right and shrunk vertically by a factor of \frac{1}{2}.. This option is true.

D. The function f(x)=\dfrac{1}{2}\sqrt{x} has the domain and the range all non-negative real values. The function  f(x)=\sqrt[3]{x} has the domain and the range all real values. So this option is false.

3 0
3 years ago
Other questions:
  • How to write a polynomial function with rational coefficients in standard form with the given zeros?
    15·1 answer
  • Jack has 2613 songs saved on his computer. Dexter has 4 times as many song's saved on his computer as jack has. how many songs d
    15·2 answers
  • HELP PLEASE!!!!! HELP
    12·2 answers
  • How many number lines comprise the basic parts of a cartesian coordinate system?
    12·2 answers
  • Find the 100th term in the arithmetic sequence<br><br> -19,-14,-9,-4,1...
    7·1 answer
  • The figure in quadrant III it the coordinate plane below is a transformation of the figure in quadrant II. The figure in quadran
    13·2 answers
  • CAN SOMEONE HELP ME WITH REFLECTIONS...ILL GIVE BRAINLEST AND POINTS​
    14·1 answer
  • Which of the following is equivalent to sqrt-75
    13·1 answer
  • HELP ME PLEASE 100 POINTS
    5·1 answer
  • Rewrite in simplest terms: –8(9r – 1) — 9(-8r + 2)
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!