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3 years ago

target sell 24 bottle of water for$3, and 36 bottle of water for $4. which is the batter buy and how much?

Mathematics

2 answers:

Ksenya-84 [330]3 years ago

5 0

Probably the 36 for 4$, but it also depends on the fluid OZ's of the bottle.

Ratling [72]3 years ago

4 0

Well, the $3 pack is giving you 24 bottles at 8 cents each. The $4 pack is giving you 36 bottles at 9 cents each. The 36 is a better deal because you're getting 12 more bottles of water than you get in the $3 pack for a better price.

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Using Order of Operations (PEMDAS), solve the following two expressions. Show all steps.

aksik [14]

Answer:

Multiple: 3 * 5 = 15

Add: 7 + the result of step No. 1 = 7 + 15 = 22

Divide: 4 / 2 = 2

Subtract: the result of step No. 2 - the result of step No. 3 = 22 - 2 = 20

Add: the result of step No. 4 + 3 = 20 + 3 = 23

Add: 7 + 3 = 10

Multiple: the result of step No. 1 * 5 = 10 * 5 = 50

Divide: 4 / 2 = 2

Subtract: the result of step No. 2 - the result of step No. 3 = 50 - 2 = 48

Add: the result of step No. 4 + 3 = 48 + 3 = 51

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2 years ago

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Violet obtained a 25 year fixed rate mortgage for $176,900 on a home that cost her $194,300. If the interest rate in the mortgag

Irina18 [472]

Answer:

$1015.67

Step-by-step explanation:

The appropriate formula for the payment amount (A) for principal P and interest rate r over time period t years is ...

A = P·(r/12)/(1 -(1 +r/12)^(-12t))

Filling in the given numbers, you get ...

A = 176,900·(.0482/12)/(1 -(1 +0.0482/12)^-300) ≈ 1015.67

Violet's monthly payment for principal and interest is $1015.67.

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3 years ago

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yanalaym [24]

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Bart’s bikes ll .50

Step-by-step explanation:

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3 years ago

What's the sum if $40 is taxxed 8.875?

Marina CMI [18]

40 x 0.08875 = 3.55
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3 years ago

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Find a particular solution to the nonhomogeneous differential equation y??+4y?+5y=?10x+e^(?x).

Firdavs [7]

Answer:

A) Particular solution:

$2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

B) Homogeneous solution:

$y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))$

C) The most general solution is

$y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

Step-by-step explanation:

Given non homogeneous ODE is

$y''+4y'+5y=10x+e^{-x}---(1)$

To find homogeneous solution:

$D^{2}+4D+5=0\\D^{2}+4D+4-4+5=0\\\\(D+2)^{2}=-1\\D+2=\pm iD=-2 \pm i\\y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))---(2)$

To find particular solution:

$y_{p}=Ax+B+Ce^{-x}\\\\y'_{p}=A-Ce^{-x}\\y''_{p}=Ce^{-x}\\$

Substituting $y_{p},y'_{p},y''_{p}$ in (1)

$y''_{p}+4y'_{p}+5y_{p}=10x+e^{-x}\\Ce^{-x}+4(A-Ce^{-x})+5(Ax+B+Ce^{-x})=10x+e^{-x}\\$

Equating the coefficients

$5Ax+2Ce^{-x}+4A+5B=10x+e^{-x}\\5A=10\\A=2\\4A+5B=0\\B=-\frac{4A}{5}B=-\frac{8}{5}2C=1\\C=\frac{1}{2}\\So,\\y_{p}=2x+\frac{1}{2}e^{-x}-\frac{8}{5}---(3)\\$

The general solution is

$y=y_{h}+y_{p}$

from (2) ad (3)

$y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

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2 years ago