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I am Lyosha [343]
2 years ago
11

Lars works as a nurse and a lumberjack. He wants to work for at most 666 days this week, and he wants to earn more than \$950$95

0dollar sign, 950. N+L \leq 6N+L≤6N, plus, L, is less than or equal to, 6 represents the number of days Lars can work as a nurse NNN and lumberjack LLL in order to work at most 666 days this week. 216N+112L > 950216N+112L>950216, N, plus, 112, L, is greater than, 950 represents the number of days Lars can work as a nurse and a lumberjack to earn more than \$950$950dollar sign, 950. Does Lars meet both of his expectations by working as a nurse for 222 days and working as a lumberjack for 444 days?
Mathematics
1 answer:
Nesterboy [21]2 years ago
8 0

Answer:

Lars works for the expected number of days but doesn't earn the expected amount of money.

Step-by-step explanation:

Let's check whether Lars works for the expected number of days this week by working as a nurse for 2 days and working as a lumberjack for 4 days. To do this, we substitute N=2 and L=4 into the first inequality:

N+L≤6

2+4≤6

6≤6

The true inequality shows that Lars works for the expected number of days this week by working as a nurse for 2 days and working as a lumberjack for 4 days.

Now let's check whether Lars earns the expected amount of money by working as a nurse for 2 days and working as a lumberjack for 4 days.

To do this, we substitute N=2 and L=4 into the second inequality.

216N+112L>950

216(2)+112(4) > 950

880 >950

​  

The false inequality shows that Lars doesn't earn the expected amount of money by working as a nurse for 2 days and working as a lumberjack for 4 days.

Lars works for the expected number of days but doesn't earn the expected amount of money.

​  

 

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