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3 years ago

B. 1/2 of 4/5 = ____ fifth(s)

Mathematics

1 answer:

MrRissso [65]3 years ago

5 0

Answer:

2 because of the way the question is written

2/5 if you get 2 wrong.

Step-by-step explanation:

1/2 * 4/5 of means multiply

numerator: 1*4 = 4

denominator = 2 * 5 = 10

Answer: 4 / 10 but this will reduce. Divide Top and Bottom by 2

4/2 = 2

10/2 = 5

Answer: 2/5

The way you should answer is 2 because the question gives you the fact that it is in 5ths. If you get it wrong then put in 2/5.

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Find the surface area of the triangular prism

ruslelena [56]

surface area of the triangular prism = 7×10 + 7.62 × 10 + 2× 0.5 × 3×7 + 3×10 cm²

=> 70 + 76.2 + 21 + 30 cm ²

=> 100 + 97.2 cm²

=> 197.2 cm² <em><u>Ans.</u></em>

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3 years ago

Simplify 6 to the negative 3rd power over 6 to the 5th.

Ugo [173]

To simplify $\frac{6^{-3}}{6^5}$
$\frac{6^{-3}}{6^5}$

$\frac{\frac{1}{6^3}}{6^5}$
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3 years ago

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What is the image of (-3,4)

UkoKoshka [18]

Answer:

(2, 3)

Step-by-step explanation:

Since the problem says to add 5 to x, and subtract from y, you can do x = -3 + 5 and y = 4 - 1 to get (2, 3)

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3 years ago

Five concert ticket cost $181.25. What is the cost of 8 concert tickets?

Roman55 [17]

Answer:$290

Step-by-step explanation:

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3 years ago

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Which of the following is not a possible number of solutions when solving a system of equations containing a quadratic and a lin

Kobotan [32]

Answer:

Step-by-step explanation:

We have a system with two equations, one equation is a quadratic function and the other equation is a linear function.

To solve this system we have to clear "y" in both equations, and then equal both equations, then we will have a quadratic function and equal it to zero:

$ax^2+bx+c=0, a\neq 0$

Then to resolve a quadratic equation we apply Bhaskara's formula:

$x_{1}=\frac{-b+\sqrt{b^2-4ac} }{2a}$

$x_{2}=\frac{-b-\sqrt{b^2-4ac} }{2a}$

It usually has two solutions.

But it could happen that $\sqrt{b^2-4ac}$ then the equation doesn't have real solutions.

Or it could happen that there's only one solution, this happen when the linear equation touches the quadratic equation in one point.

And it's not possible to have more than 2 solutions. Then the answer ir 3.

For example:

In the three graphs the pink one is a quadratic function and the green one is a linear function.

In the first graph we can see that the linear function intersects the quadratic function in two points, then there are two solutions.

In the second graph we can see that the linear function intersects the quadratic function in only one point, then there is one solutions.

In the third graph we can see that the linear function doesn't intersect the quadratic function, then there aren't real solutions.

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3 years ago