Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.

Given,

n = 66

We know that,

According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:

$k=1+log_{2} n$

Here, n is equal to 66 and by substituting the value to the equation we get:

$k=1+log_{2} (66)$

k = 7.0444

k ≈ 7

Learn more about Sturge's rule here: brainly.com/question/28184369

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8 0

1 year ago

Solve this problem in your notebook using all four steps. Harvey is 3 times as old as Jane. The sum of their ages is 48 years. F

Reil [10]

Answer:

Jane is 12 and Harvey is 36

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

65=91/?<br> What is the question mark

trapecia [35]

I would write the missing variable as x. It's what everyone uses.
Anyway, 91 divided by x is 65.
The way we can do this is reverse 65 and x.
91 divided by 65 = x.

91 divided by 1.4 = 65
65 x 1.4 = 91

x (or ?) = 1.4

5 0

3 years ago

Naglakad si Ruben ng 900 sentimetro samantalang si Jaime ay naglakad ng

Gelneren [198K]

Sagot:

100 cm

Hakbang-hakbang na paliwanag:

Kung ganoon :

Distansya na sakop ng Ruben = 900 centimetri

Distansya na sakop ng Jamie = 10 metro

Pagko-convert sa centimeter:

100 cm = 1 m

x cm = 10 m

Paggamit ng multiplikasyon ng krus:

x = 100 * 10

x = 1000 cm.

Dahil dito Distansya ni Jamie = 1000 cm

Distansya sa pagitan ng Jamie at Ruben;

1000 cm - 900 cm = 100 cm

3 0

3 years ago