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Sophie [7]
3 years ago
10

HELLPPPPPP FASTTT !!

Chemistry
2 answers:
alina1380 [7]3 years ago
8 0
AND OCYGENAND OXYGEN!!
** hope this helps
tino4ka555 [31]3 years ago
3 0

I think the answer is oxygen. If i am wrong I am sorry.

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Find how many milliliters of NaOH should be used to reach the half-equivalence point during the titration of 20.00 mL 0.888 M bu
Varvara68 [4.7K]

<u>Answer:</u> The volume of NaOH solution required to reach the half-equivalence point is 0.09 mL

<u>Explanation:</u>

The chemical equation for the dissociation of butanoic acid follows:

CH_3CH_2CH_2COOH\rightleftharpoons CH_3CH_2CH_2COO^-+H^+

The expression of K_a for above equation follows:

K_a=\frac{[CH_3CH_2CH_2COO^-][H^+]}{[CH_3CH_2CH_2COOH]}

We are given:

[CH_3CH_2CH_2COOH]=0.888M\\K_a=1.54\times 10^{-5}

[CH_3CH_2CH_2COO^-]=[H^+]

Putting values in above expression, we get:

1.54\times 10^{-5}=\frac{[H^+]^2}{0.888}

[H^+]=-0.0037,0.0037

Neglecting the negative value because concentration cannot be negative

To calculate the volume of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is butanoic acid

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=\frac{0.0037}{2}M\text{ (half equivalence)}\\V_1=20.00mL\\n_2=1\\M_2=0.425M\\V_2=?mL

Putting values in above equation, we get:

1\times \frac{0.0037}{2}\times 20.00=1\times 0.425\times V_2\\\\V_2=\frac{1\times 0.0037\times 20}{1\times 0.425\times 2}=0.087mL

Hence, the volume of NaOH solution required to reach the half-equivalence point is 0.09 mL

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