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Dimas [21]
3 years ago
8

If you start a chemical reaction with 38 grams of reactants, how many grams of a product would

Chemistry
1 answer:
aniked [119]3 years ago
7 0

Answer:

38 g as well due to the law of conservation of mass.

Explanation:

Hello,

In this case, we need to review the law of conservation of mass which states that matter cannot be neither created nor destroyed, thus, for chemical reactions, the mass of reactants at the beginning of the chemical reaction must equal the mass of products at the end in closed systems, that is why, since 38 g is the mass of reactants, the mass of the overall products is also 38 g.

Best regards.

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Answer:

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Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0 C, the pr
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The question is incomplete, here is the complete question:

Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0°C, the pressure is 0.230 atm. What is the likely formula of the compound?

A. XeO

B. XeO_4

C. Xe_2O_2

D. Xe_2O_3

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<u>Answer:</u> The chemical formula of the compound is XeO_4

<u>Explanation:</u>

To calculate the molecular weight of the compound, we use the equation given by ideal gas equation:

PV = nRT

Or,

PV=\frac{w}{M}RT

where,

P = Pressure of the gas = 0.230 atm

V = Volume of the gas  = 50.0 mL = 0.050 L     (Conversion factor:  1 L = 1000 mL)

w = Weight of the gas = 0.100 g

M = Molar mass of gas  = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gas = 0^oC=273K

Putting value in above equation, we get:

0.230\times 0.050=\frac{0.100}{M}\times 0.0821\times 273\\\\M=\frac{0.100\times 0.0821\times 273}{0.230\times 0.050}=194.9g/mol\approx 195g/mol

The compound having mass as calculated is XeO_4

Hence, the chemical formula of the compound is XeO_4

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