How many grams of H2 are needed to react with 47 grams of N2 to produce 200 grams of NH3?

sp2606 [1]

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

is a combustion reaction

Explanation:

In a combustion reaction a chemical substance (usually organic substances) are reacted with oxygen to form the most stable oxides and heat.

CH₄ + 2 O₂ → CO₂ + 2 H₂O

In a double displacement reaction two compounds exchange elements.

AB + CD → AC + BD

In a decomposition reaction a compound is split into simpler substances.

AB → A + B

In a synthesis reaction two elements are combined to form another compound. A + B → AB

In a single displacement reaction a compound exchange one of its elements.

AB + C → AC + B

Learn more about:

types of chemical reactions

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8 0

3 years ago

How many amps are required to produce 75. 8 g of iron metal from a solution of aqueous iron(iii)chloride in 6. 75 hours?

Shalnov [3]

The amount of current required to produce 75. 8 g of iron metal from a solution of aqueous iron (iii)chloride in 6. 75 hours is 168.4A.

The amount of Current required to deposit a metal can be find out by using The Law of Equivalence. It states that the number of gram equivalents of each reactant and product is equal in a given reaction.

It can be found using the formula,

m = Z I t

where, m = mass of metal deposited = 75.8g

Z = Equivalent mass / 96500 = 18.6 / 96500 = 0.0001

I is the current passed

t is the time taken = 75hour = 75 × 60 = 4500s

On subsituting in above formula,

75.8 = E I t / F

⇒ 75.8 = 0.0001 × I × 4500

⇒ I = 168.4 Ampere (A)

Hence, amount of current required to deposit a metal is 168.4A.

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7 0

2 years ago

What is the concentration of NaCl in a solution if titration of 15.00 mL of the solution with 0.2503 M AgNO3 requires 20.22 mL o

Nina [5.8K]

Answer:

The concentration of NaCl = 0.3374 M

Explanation:

Given :

Molarity of AgNO₃ = 0.2503 M

Volume of AgNO₃ = 20.22 mL

The conversion of mL into L is shown below:

$1 mL= 10^{-3} L$

Thus, volume of the solution = 20.22×10⁻³ L

Molarity of a solution is the number of moles of solute present in 1 L of the solution.

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

The formula can be written for the calculation of moles as:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Thus,

$Moles\ of\ AgNO_3 =Molarity \times {Volume\ of\ the\ solution}$

$Moles\ of\ AgNO_3 =0.2503 \times {20.22\times 10^{-3}}\ moles$

$Moles\ of\ AgNO_3 = 5.0611 \times 10^{-3} moles$

The chemical reaction taking place:

$AgNO_3_(aq) + NaCl_(aq) \rightarrow AgCl_(s) + NaNO_3_(aq)$

According to reaction stoichiometry:

1 mole of AgNO₃ reacts with 1 mole of NaCl

Thus,

5.0611×10⁻³ moles of AgNO₃ reacts with 5.0611×10⁻³ moles of NaCl

Thus, moles of NaCl required = 5.0611×10⁻³ moles

Volume of NaCl required = 15.00 mL

The conversion of mL into L is shown below:

$1 mL= 10^{-3} L$

Thus, volume of the solution = 15.00×10⁻³ L

Applying in the formula of molarity as:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity\ of\ NaCl=\frac{5.0611\times 10^{-3}}{15.00\times 10^{-3}}$

$Molarity\ of\ NaCl= 0.3374 M$

Thus, the concentration of NaCl = 0.3374 M

6 0

3 years ago

Lucille is finding it difficult to play soccer after school. Her doctor thinks that her cells might not be getting enough oxygen

Natali5045456 [20]

Answer:

They might not be bringing in enough oxygen from the air. It's hard to play soccer if you don't have enough oxygen in your cells. They might not be breaking down starch to make glucose.

Explanation:

6 0

2 years ago

The mass of cupric sulfate needed to make .5 liters of a .5M solution is

dalvyx [7]

Answer:

C

Explanation:

3 0

3 years ago