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SCORPION-xisa [38]
4 years ago
9

How many grams of H2 are needed to react with 47 grams of N2 to produce 200 grams of NH3?

Chemistry
1 answer:
Oduvanchick [21]4 years ago
5 0
I think it’s law conservation of mass.

So 200g(NH3)-47g(N2)=153g(H2)

H2+N2—->NH3
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How many molecules are in 3.6 grams of NaCl? Question options:
Levart [38]

Answer:

\boxed {\boxed {\sf 3.7 * 10^{22} \ molecules \ NaCl}}

Explanation:

We are asked to find how many molecules are in 3.6 grams of sodium chloride.

<h3>1. Convert Grams to Moles </h3>

First, we convert grams to moles using the molar mass. These values are equivalent to atomic masses on the Periodic Table, but the units are grams per moles instead of atomic mass units. Look up the molar masses of the individual elements: sodium and chlorine.

  • Na: 22.9897693 g/mol
  • Cl: 35.45 g/mol

There are no subscripts in the chemical formula (NaCl), so we simply add the 2 molar masses.

  • NaCl: 22.9897693 + 35.45 = 58.4397693 g/mol

Now we will convert using dimensional analysis. First, set up a ratio using the molar mass.

\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}

We are converting 3.6 grams to moles, so we must multiply the ratio by this value.

3.6 \ g \ NaCl *\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}

Flip the ratio so the units of grams of sodium chloride cancel.

3.6 \ g \ NaCl *\frac { 1 \ mol \ NaCl}{58.4397693 \ g \ NaCl}

3.6  *\frac { 1 \ mol \ NaCl}{58.4397693}

\frac { 3.6}{58.4397693} \ mol \ NaCl

0.06160188589 \ mol \ NaCl

<h3>2. Convert Moles to Molecules </h3>

Next, we convert moles to molecules using Avogadro's Number. This is 6.022 × 10²³ and it tells us the number of particles (atoms, molecules, formula units, etc). In this case, the particles are molecules of sodium chloride. Let's set up another ratio.

\frac {6.022 \times 10^{23} \ molecules \ NaCl}{ 1 \ mol \ NaCl}

Multiply by the number of moles we calculated.

0.06160188589 \ mol \ NaCl * \frac{6.022 \times 10^{23} \ molecules \ NaCl}{1 \ mol \ NaCl}

The units of moles of sodium chloride cancel.

0.06160188589 * \frac{6.022 \times 10^{23} \ molecules \ NaCl}{1 }

3.70966557*10^{22} \ molecules \ NaCl

<h3>3. Round </h3>

The original measurement of grams (3.6) has 2 significant figures, so our answer must have the same. For the number we found, that is the tenths place. The 0 in the hundredth place tells us to leave the 7 in the tenth place.

3.7 * 10^{22} \ molecules \ NaCl

There are 3.7 * 10^{22} \ molecules \ NaCl in 3.6 grams and the correct answer is choice D.

5 0
3 years ago
URGENT PLEASE HELP!!!
mote1985 [20]
Even though two grams seemed to disappear or vanish, the law of conversation of mass still holding true. Mercuric oxide, when heated, forms a gas of mercury and oxygen. During the investigation, some gas could have escaped or evaporated.
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3 years ago
Read 2 more answers
What controls the viscosity of lava?
prohojiy [21]
Silica content, temperature and gas content. The resistance and Heat are some of the things that control the viscosity of lava
5 0
4 years ago
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A student measured the gram weight of a
e-lub [12.9K]

Answer:  0.428%

Explanation:  % Error = [(measured - Actual)/Actual]*100%

    (93.9g - 93.5 g)/93.5g = 0.428%

5 0
3 years ago
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What is the specific heat of a substance if 1450 calories are required to raise the temperature of a 240g sample by 20℃?
bazaltina [42]

Answer:

6960 J/kg°C

Explanation:

specific heat= mass×specific heat capacity×increase in temperature

specific heat= 0.240×1450×20= 6960 J/kg°C

hope it helps!

5 0
3 years ago
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