First one (ignore22222323333333)
By solving a linear equation, we will see that the total cost for renting the bus is $90.
<h3>What was the total cost of renting the bus, in dollars?</h3>
Let's say that the total cost is C.
When there are 20 students, each student should pay:
p = C/20
When the other 10 students are added (for a total of 30) each student pays:
p' = C/30.
We know that the cost for each of the original 20 students decreased by $1.50, so:
p' = p - $1.50
Then we have 3 equations to work with:
p = C/20
p' = C/30.
p' = p - $1.50
Now we can replace the first and second equations into the third one:
C/30 = C/20 - $1.50
Now we can solve this linear equation for C:
C/20 - C/30 = $1.50
C*( 1/20 - 1/30) = $1.50
C*(30/600 - 20/600) = $1.50
C*(10/600) = $1.50
C*(1/60) = $1.50
C = 60*$1.50 = $90
So the total cost for renting the bus is $90.
If you want to learn more about linear equations:
brainly.com/question/1884491
#SPJ1
Answer:
Step-by-step explanation:
First we need to write in correct form :
We know how to divide fractions. If we can divide numerator by numerator, denominator by denominator, we just do it. In this example we can not do that.
So, we rewrite first fraction and multiply by reciprocal second ( numerator and denominator change place)
Now, multiply numerator by numerator, denominator by denominator :
<span>Dealing with finances becomes more difficult when working on a commission basis because unlike working on a salary basis, there is no regular pay. A commission means that earnings are based on rate of sale or number of completed tasks. Income may be reduced if you do not sell enough, or fail to complete enough tasks.</span>
Answer:
Play 3
Step-by-step explanation:
Given:
Required [Missing from the question]:
Determine the play with the least change in yard?
To do this, we ignore the sign in front of each yard before we analyze.
So, we have:
Play 1 has a change of 4
Play 2 has 6
Play 3 has 2
Play 4 has 3
<em>From the above analysis, play has the least (which is 2)</em>
