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timofeeve [1]
3 years ago
8

Is 3x^3-12x a difference of squares​

Mathematics
1 answer:
Aneli [31]3 years ago
7 0

Answer:

3x(x+2)(x−2 )

Hope this helps

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HELP ASAP MArking AS BRAINLIST
Fed [463]

Answer:

80 because the sum of a triangle should be 180 so 180 - 100 is 80

7 0
3 years ago
RU and JM are diagonals. Given ST= 6, KL = 10, and RU= 12, find JM
AfilCa [17]

Your question is incomplete. The complete question is attached down

Answer:

JM = 20 units

Step-by-step explanation:

∵ Hexagon RSTUVW is similar to hexagon  JKLMNP

∴ The corresponding sides and diagonals have a constant ratio

∴ \frac{RS}{JK}=\frac{ST}{KL}=\frac{TU}{LM}=\frac{UV}{MN}=\frac{VW}{NP}=\frac{RW}{JP}=\frac{RU}{JM}

∵ ST = 6 units

∵ KL = 10

∴ \frac{ST}{KL}=\frac{6}{10}

- Simplify it by dividing up and down by 2

∴ \frac{ST}{KL}=\frac{3}{5}

∵ \frac{ST}{KL}=\frac{UR}{JM}

∵ RU = 12 units

∴  \frac{3}{5}=\frac{12}{JM}

- By using cross multiplication

∴ JM × 3 = 5 × 12

∴ 3 JM = 60

- Divide both sides by 3

∴ JM = 20 units

5 0
3 years ago
f the probability of being hospitalized during a year is 0.25 ​, find the probability that no one in a family of five will be ho
Kaylis [27]

Answer:

The probability that no one in a family of five will be hospitalized in a year is 0,2373

Step-by-step explanation:

Let p denote the probability of being hospitalized during a year,

Then p=0.25

And p' the probability of not being hospitalized during a year is 1-p

Thus p' = 1-p = 1-0.25 = 0.75

The probability that no one in a family of five will be hospitalized in a year is equal to p'^{5}. That is

p'^{5} = 0.75^{5} ≈ 0,2373

3 0
3 years ago
What number is three less than five hundred and one?
Oduvanchick [21]
Five hundred and one = 501
three = 3

501-3 = 498 or four hundred and ninety eight
3 0
3 years ago
Read 2 more answers
Point b lies on the segment ac . Find the length of the segment ac, if ab=7.8 cm, bc=25mm. How many different solutions can this
mixas84 [53]

Given that B lies on segment AC and AB=7.8cm , BC = 25mm

Let us convert AB to mm by multiplying with 10 that is AB = 78mm

There are totally 3 possible  ways for B lying on segment AC.

Solution 1:- B lies in between A and C,

Then AC = AB+BC

               =78+25 = 103 mm

Solution 2:- B lies to the right of C like ACB.

Then AB = AC+CB

         78 = AC+25

         AC = 78-25 = 53mm

Solution 3:- B lies to the left of A like BAC.

Then BC = BA+AC

          25 = 78+AC

Since AC cannot be negative, this way is not possible.

Hence there are only 2 solutions possible.

If we are given that B lies on line joining A and C, then definitely B should lie between A and C.  That means nothing but solution 1. So only one solution is possible in this case.

5 0
3 years ago
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