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3 years ago

Find the value of |5| - 4(32 - 2).

Mathematics

2 answers:

JulsSmile [24]3 years ago

6 0

Answer:

- 115

Step-by-step explanation:

Given

| 5 | - 4(32 - 2)

= 5 - 4(30)

= 5 - 120

= - 115

Dmitriy789 [7]3 years ago

6 0

Answer:

-115

Step-by-step explanation:

5-4(32-2)

(4×30) = 120

5 - 120=

-115

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Answer:

The Moon is an average of 238,855 miles (384,400 km) away

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Suppose that the second term of a geometric sequence is 4 and the sixth term is 16. Find the fourth term

Kaylis [27]

Answer:

Step-by-step explanation:

<h3>Given GP</h3>

a₂ = 4,
a₆ = 16

a₄ = ?

<h3>Solution</h3>

a₂ = ar = 4
a₆= ar⁵ = 16

<u>Substitute ar in the second equation</u>

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r⁴ = 4
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<u>Then finding a₄</u>

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2 years ago

There are 2.54cm in an inch, 12 inches in a foot, and 5,280 feet in a mile.which expression gives the number of centimeters in a

geniusboy [140]

Answer:

(2.54×12) ×5280

Step-by-step explanation:

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8 0

3 years ago

An inequality is shown below.

Stells [14]

B.
You are looking for something that does not let 25x go over 80.

8 0

3 years ago

第 5 个问题 a multiple choice exam has 10 questions. each question has 3 possible answers, of which one is correct. a student knows

tatuchka [14]

The chances that the student was merely guessing is 1/3.

Bayes Theorem determines the conditional probability of an event A given that event B has already occurred.

denoted by

$P(A/B)=\frac{P(A)*P(B/A)}{P(B)}$

let A be the event that the student knows the answer .

B be the event that the student does not knows the answer .

and

E be the event he gets answer correct .

According to the given question

$P(A)=\frac{4}{10} \\\\ P(B)=1-\frac{4}{10} =\frac{6}{10}$

Probability that the answer is correct ,given that he knows the answer is

$P(E/A)=1$

Probability that the answer is correct ,given that he guesses it is

$P(E/B)=\frac{1}{3}$ [as the MCQ has 3 options and only one is correct]

We need to find the probability that he guesses the answer given that it is correct.

Required probability $P(B/E)=\frac{P(B)*P(E/B)}{P(A)*P(E/A)+P(B)*P(E/B)}$

Substituting the values we get

$P(B/E)=\frac{\frac{6}{10} *\frac{1}{3} }{\frac{4}{10} *1+\frac{6}{10} *\frac{1}{3} }$

$=\frac{6}{30}*\frac{30}{18} \\ \\ =\frac{6}{18} \\ \\ =\frac{1}{3}$

Therefore , the chances that the student was merely guessing is 1/3.

Learn more about Probability here brainly.com/question/13140147

#SPJ4

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8 months ago