Answer:
715 ft^2
Step-by-step explanation:
Sorry, don't even think i've learned this yet, maybe look up a video from khan academy?
Answer:
16.5 square units
Step-by-step explanation:
You are expected to integrate the function between x=1 and x=4:

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<em>Additional comment</em>
If you're aware that the area inside a (symmetrical) parabola is 2/3 of the area of the enclosing rectangle, you can compute the desired area as follows.
The parabolic curve is 4-1 = 3 units wide between x=1 and x=4. It extends upward 2.25 units from y=4 to y=6.25, so the enclosing rectangle is 3×2.25 = 6.75 square units. 2/3 of that area is (2/3)(6.75) = 4.5 square units.
This region sits on top of a rectangle 3 units wide and 4 units high, so the total area under the parabolic curve is ...
area = 4.5 +3×4 = 16.5 . . . square units
1.) move the constant over (1/2x=18-6) || 2.) combine like terms (1/2x=12) || 3.) divide both sides by 1/2 to get x alone (x=6)
Answer: see proof below
<u>Step-by-step explanation:</u>
Use the following Half-Angle Identities: tan (A/2) = (sinA)/(1 + cosA)
cot (A/2) = (sinA)/(1 - cosA)
Use the Pythagorean Identity: cos²A + sin²B = 1
Use Unit Circle to evaluate: cos 45° = sin 45° = 
<u>Proof LHS → RHS</u>
Given: 
Rewrite Fraction: 
Half-Angle Identity: 
Substitute: 
Simplify: 




= 2
LHS = RHS: 2 = 2 