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3 years ago

Razi’s Party Favor Bag Progress

Mathematics

2 answers:

k0ka [10]3 years ago

8 0

Answer:

Step-by-step explanation:

right for edg

KIM [24]3 years ago

3 0

Answer:

1 less bag

Step-by-step explanation:

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6. Are these triangles similar? If they are, name the postulate or theorem that proves they are.

TiliK225 [7]

C by AA- bc 180 degrees in a triangle

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2 years ago

Equation that has a slope of -4 and passes through the point (-2, 2) show work too

Alenkinab [10]

Answer:

y=-4x-6

Step-by-step explanation:

y=mx+b, where m is the slope and b is the y-intercept

Slope is given as -4, so:

y=-4x+b

To find b, sub in the point we were given (-2,2):

2=-4(-2)+b

2=8+b

b=2-8=-6

So we have: y=-4x-6

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2 years ago

Drag tiles to fill in the blanks to complete the expression that could be used to predict the number of winners of a game. Tiles

ziro4ka [17]

Answer:

First blank - A)Total Number of Possible Outcomes

Second blank - B)Number of Winners

Step-by-step explanation:

The exact question is as follows :

We know that,

Probability of an event is equals to Total number of Favorable outcomes divided by Total number of outcomes

So,

P(event) = Number of favorable outcomes ÷ Total Number of Possible Outcomes

As we have to predict the Number of winners of a game

So,

P(Number of winner) = Number of winners ÷ Total number of Contestants

∴ we get

P(event) = Number of favorable outcomes ÷ Total Number of Possible Outcomes

= Number of winners ÷ Total number of Contestants

4 0

2 years ago

Help me please due in 2 minutes

frez [133]

7:4 is the constant and is your answer

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2 years ago

Read 2 more answers

A circle has the equation 2x²+12x+2y²−16y−150=0.

KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

$(x-h)^{2} +(y-k)^{2}=r^{2}$ (1)

Where $(h,k)$ are the coordinates of the center and $r$ is the radius.

Now, we are given the equation of this circle as follows:

$2x^{2}+12x+2y^{2}-16y-150=0$ (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

$2(x^{2}+6x+y^{2}-8y-75)=0$ (3)

Rearranging the equation:

$x^{2}+6x+y^{2}-8y=75$ (4)

$(x^{2}+6x)+(y^{2}-8y)=75$ (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of $(a\pm b)^{2}=a^{2}\pm+2ab+b^{2}$ :

For the first parenthesis:

$x^{2}+6x+b^{2}$

We can rewrite this as:

$x^{2}+2(3)x+b^{2}$

Hence in this case $b=3$ and $b^{2}=9$ :

$x^{2}+2(3)x+3^{2}=x^{2}+6x+9=(x+3)^{2}$

For the second parenthesis:

$y^{2}-8y+b^{2}$

We can rewrite this as:

$y^{2}-2(4)y+b^{2}$

Hence in this case $b=-3$ and $b^{2}=9$ :

$y^{2}-2(4)y+4^{2}=y^{2}-8y+16=(y-4)^{2}$

Then, equation (5) is rewritten as follows:

$(x^{2}+6x+9)+(y^{2}-8y+16)=75+9+16$ (6)

Note we are adding 9 and 16 in both sides of the equation in order to keep the equality.

Rearranging:

$(x-3)^{2}+(y-4)^{2}=100$ (7)

At this point we have the circle equation in the center radius form $(x-h)^{2} +(y-k)^{2}=r^{2}$

Hence:

$h=-3$

$k=4$

$r=\sqrt{100}=10$

8 0

3 years ago