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Korolek [52]
4 years ago
13

What is the ratio AC: CB?​

Mathematics
1 answer:
sergij07 [2.7K]4 years ago
3 0

Answer:

how do we find this out

Step-by-step explanation:

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Suppose your friends have the following ice cream flavor preferences: 70% of your friends like Chocolate (C). The remaining do n
Marianna [84]

Answer:

  B.  0.18

Step-by-step explanation:

I find the question oddly worded. Apparently, 25% of 70% of your friends like Chocolate and also like Sprinkles. You need to find the product of these numbers to determine the proportion of friends who like Chocolate that also like Sprinkles. That product is ...

  0.25·0.70 = 0.175 ≈ 0.18 . . . . matches choice B

5 0
3 years ago
If f(x) is a linear function and the domain of f(x) is the set of all real numbers, which statement cannot be true?
Georgia [21]

Answer:

The Answer is C.

Step-by-step explanation:

6 0
4 years ago
What are the answers for the chart in number 4,5,6
svetoff [14.1K]
#4(1)=-1. (2)=5. (3)=14. (4)=26 srry but all i know hoped i helped

[how i did]

the first one i did 3×-5+14 which equals -1
and the second one is the same two 3×-3+14=5 you just add the the number on B
7 0
3 years ago
Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )
Zina [86]

Answer:

\purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

Step-by-step explanation:

\cos( \alpha ) =  \frac{ \sqrt{6} }{6}  =  \frac{1}{ \sqrt{6} }  \\  \\  \therefore \:  \sin( \alpha )  =  \sqrt{1 -  { \cos}^{2} ( \alpha ) }  \\  \\  =  \sqrt{1 -  \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} }  \\  \\ =  \sqrt{1 -  {\frac{1}{ {6} }}}  \\  \\ =  \sqrt{ {\frac{6 - 1}{ {6} }}}   \\  \\  \red{\sin( \alpha ) =  \sqrt{ { \frac{5}{ {6} }}} } \\  \\  \tan( \alpha ) =  \frac{\sin( \alpha ) }{\cos( \alpha ) }  =  \sqrt{5}  \\  \\ \sin( \beta )  =  \frac{ \sqrt{2} }{4}  \\  \\  \implies \: \cos( \beta )  =   \sqrt{ \frac{7}{8} }  \\  \\ \tan( \beta )  =  \frac{\sin( \beta ) }{\cos( \beta ) } =  \frac{1}{ \sqrt{7} }   \\  \\  \tan( \alpha  -  \beta ) =  \frac{ \tan \alpha  -  \tan \beta }{1 +  \tan \alpha .  \tan \beta}  \\  \\  =  \frac{ \sqrt{5} -  \frac{1}{ \sqrt{7} }  }{1 +  \sqrt{5} . \frac{1}{ \sqrt{7} } }  \\  \\  =  \frac{ \sqrt{35} - 1 }{ \sqrt{7}  +  \sqrt{5} }  \\  \\  \purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

8 0
3 years ago
The distributive property can be applied to which expression to factor 12x3 – 9x2 + 4x – 3?
Arturiano [62]

Answer:

(4x - 3)(3x² + 1)

Step-by-step explanation:

Given

12x³ - 9x² + 4x - 3 ( factor the first/second and third/fourth terms )

= 3x²(4x - 3) + 1(4x - 3) ← factor out (4x - 3) from each term

= (4x - 3)(3x² + 1) ← in factored form

8 0
3 years ago
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