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Damm [24]
3 years ago
7

Nita runs 6 miles in 54 minutes. what is the rate in minutes per mile

Mathematics
2 answers:
drek231 [11]3 years ago
8 0

Answer:

a 6x54=324 mile per minute

Step-by-step explanation:

bulgar [2K]3 years ago
7 0

Answer:

The answer is 324 mile per minute.

Step-by-step explanation:

54 x 6 = 324 minutes/mile.  I hope you got your answer :) Nice question, I just figured out this question :)

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What is the LCD of 1/2 and 3/5
bagirrra123 [75]

Answer:

10

Step-by-step explanation:

How you find LCD (lowest common denominator) is that you have to look at the denominator (the bottom number) and try to find the lowest multiple between both of the numbers that is on the bottom (in this case it is 2 and 5). Sometimes you have to multiply both denominators together to get a LCD.

Example of multiplying two denominators together to get an LCD:

1/3 and 1/13 LCD is 39 because you multiply 3 and 13.

1/5 and 1/4 LCD is 20 because you multiply 5 and 4.

8 0
3 years ago
Identify the dependent variable in the situation. Coat sales go up when it is cold outside.
dolphi86 [110]
In Autumn it goes up
3 0
3 years ago
CHECK MY ANSWERS SOMEONE
Galina-37 [17]

Option A is correct.

Step-by-step explanation:

We need ti identify the radius of circle.

The radius of circle is a length of the line from center of the circle to anywhere on the edge of circle. It is also shown in the figure attached.

From the given options, only FE is the line that goes from center of circle to the edge of circle. So, FE is the radius of the circle.

So, Option A is correct.

Keyword: Radius of circle

Learn more about Radius of circle at:

  • brainly.com/question/13096001
  • brainly.com/question/1952668
  • brainly.com/question/3055705

#learnwithBrainly

7 0
3 years ago
Pls help with 29..tank you
trapecia [35]

Answer:

See below

Step-by-step explanation:

Let the  2 roots be  A and A^2.

Then A^3 = c/a and A + A^2 = -b/a.

Using the identity a^3 b^3 = (a + b)^3 - 3ab^2 - 3a^2b:-

A^3 + (A^2)^3 =  ( A + A^2)^3 - 3 A.A^4 - 3 A^2. A^2

= (A + A^2)^3 - 3A*3( A + A^2)

Substituting:-

c/a + c^2/a^2 = (-b/a)^3 - 3 (c/a)(-b/a)

Multiply through by a^3:-

a^2c + ac^2 = -b^3 + 3abc

Factoring:-

ac(a + c) = 3abc - b^3

This is not the formula required in the question but let's see if the formula in the question reduces to this. If it does we have completed the proof.

a(c - b)^3 = a(c^3 - 3c^2b + 3cb^2 - b^3) = ac^3 - 3ac^2b + 3acb^2 - ab^3

c(a - b)^3 = c(a^3 - 3a^2b + 3ab^2 - b^3) = ca^3 - 3a^2bc + 3acb^2 - cb^3.

These are equal so we have

ca^3 - 3a^2bc + 3acb^2 - cb^3 = ac^3 - 3abc^2 + 3acb^2 - ab^3

The 3acb^2 cancel out so we have:-

a^3c - ac^3 =  3a^2bc - 3abc^2 + b^3c - ab^3

ac(a^2 - c^2) = 3abc( a - c) + b^3(c - a)

ac(a + c)(a -c) = 3abc(a - c) - b^3 (a - c)

Divide through by (a - c):-

ac(a + c) = 3abc - b^3 , which is the result we got earlier.

This completes the proof.

 

3 0
3 years ago
Read 2 more answers
Helpp fast please i will give brainliest thank you so much
enot [183]
B= 5,3
c=4,-1
a=2,1
this is the answer to part c
8 0
3 years ago
Read 2 more answers
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