Answer:
(a) E(X) = 3
(b) Var(X) = 12.1067
Explanation:
(a) E[X]
E[X]T = E[X]T=A + E[X]T=B + E[X]T=C
= (2.6 + 3 + 3.4)/3
= 2.6 (1/3) + 3(1/3) + 3.4(1/3)
= 2.6/3 + 1 + 3.4/3
= 3
(b) Var (X) = E[X²]−(E[X])²
Recall that if Y ∼ Pois(λ), then E[Y 2] = λ+λ2. This implies that
E[X²] = [(2.6 + 2.6²) + (3 + 3²) + (3.4 + 3.4²)]/3
= (9.36 + 12 + 14.96)/3
= 36.32/3
= 12.1067
Var(X) = E[X²]−(E[X])²
= 12 - 3²
= 12.1067 - 9
= 3.1067
Answer:
D. Capacity
Explanation:
In order to applying for a loan, the financial institution analyze the borrower information in terms of creditworthiness i.e. collateral property, cash on hand, repayment conditions, status of the job. These factors should be based on the capacity of the borrower whether he or she is eligible for a loan or not
Therefore according to the given situation, the option D is correct and the same is to be considered
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Hope this helps!!!
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Answer:
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Explanation: