Answer:
The right alternative is Option D (0.78 V).
Explanation:
According to the question,
The cell potential will be:
=
By putting the values, we get
=
=
Thus the above is the correct option.
Answer:
The anode is oxidized and the cathode is reduced, in this way we are facing a redox reaction or oxide reduction.
Where the oxygenated compound oxidizes, and the protonized reduces.
Explanation:
When he says that oxygen is reduced the reaction would be:
OXYGEN + H (+1) -----> OH-
And the reaction where solid aluminum hydroxide is formed will be:
Al (+3) + 3 KOH (aqueous) -------> Al (OH) 3 (solid) + 3 K (+1),
Here we see how aluminum is immersed in an aqueous medium and becomes a solid compound in the form of hydroxide, where when attached to an oxygen, it is oxygenated and oxidized.
This reaction is considered irreversible
Answer: [H3O+] > [OH-] and Kw = 1 x 10 -14
Explanation:
i just had this question and tried to look it up and i got it right by guessing my bad but i hope this is ur answer as well
Answer:
Find the limiting reactant.
Explanation:
Using the ratio in the chemical formula, find the limiting reactant.
The second equation results in less mol of MnO₃, therefore it is the limiting reactant and changing the moles of O₂ to moles of MnO₃ which will give the theoretical yield which is 1.55 mol MnO₃.
Kekulé/Vant Hoff and Le Bel?