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PIT_PIT [208]
3 years ago
15

How many molecules are in 5.00 grams of NH3?

Chemistry
1 answer:
DanielleElmas [232]3 years ago
6 0

Answer:

C. 1.77x 1023

Explanation:

Not sure please correct me if im wrong

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The ideal gas law is a combination of all the gas laws and states that PV = nRT. The value of n stands for
dimaraw [331]

Answer:

d

Explanation:

p is pressure, v is vo;lume, t is temperature, r is ideal gas contstant, therefore n is the moles

7 0
3 years ago
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a 20.4 g aluminum sphere and a 49.4 g iron sphere are both added to 75.2 mL of water contained in a graduated cylinder. what is
alexandr1967 [171]
The level in the beaker will increase because the volumes of the spheres will also be added to the volume of the water. First, we must determine the volume of each sphere. For this, we will use:

density = mass / volume
We can check the density of both aluminum and iron in literature, and given the mass, we may obtain the volume. 

Aluminum:
Density = 2.70 g/ml
Mass = 20.4 g
Volume = 20.4 / 2.7 = 7.56 ml


Iron:
Density = 7.87 g/ml
Mass = 49.4 g
Volume = 49.4 / 7.87 = 6.28 ml

Now, we add these volumes to the volume of water present:
75.2 + 6.28 + 7.56 = 89.04

The new level will be 89.0 ml
3 0
3 years ago
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Our exact distance from the sun varies throughout the year due to Earth's elliptical
zloy xaker [14]

Answer:

The earth being tilted towards the sun in the summer.

Explanation:

Even though the earth is in the same place, the angle towards the sun is different.

3 0
3 years ago
do you agree or disagree with the following statement: laws are more important than theories because were never really sure is t
Vladimir [108]

Answer:

I agree with laws.

Explanation:

because laws are always correct.

6 0
3 years ago
The data below refer to the following reaction: 2NO(g) + I2(g) 2NOI(g) Concentration (M) [NO] [I2] [NOI] Initial 2.0 4.0 1.0 Equ
anygoal [31]

Answer:

3.5 mol·L⁻¹  

Explanation:

1. Set up an ICE table.

\begin{array}{cccccc}\text{2NO} & + & \text{I}_{2} &\, \rightleftharpoons \, & \text{2NOI} & & \\ 2.0 &   &  4.0 &   & 1.0 &  & \\ -2x &   & -x &   & +2x &  &  \\ 2.0-2x &   & 4.0-x &   & 1.0+2x &  & \\\end{array}

2. Solve for x

The equilibrium concentration of NO is 1.0 mol·L⁻¹, so

       1.0 = 2.0 - 2x

2x + 1.0 = 2.0

        2x =  1.0

          x = 0.5

3. Calculate the equilibrium concentration of I₂

[I₂] = 4.0 - x = 4.0 - 0.5 = 3.5 mol·L⁻¹

4 0
3 years ago
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