Answer:
√ 1. Cellphone
<h3>Product Description:</h3>
A cellphone is any portable telephone that uses cellular network technology to make and receive calls.
Answer:
1) is to stretch or do some workouts
2) is to read
3) is to play outside for an hour
4) is to do gardening
5) is rest
It stands for arithmetic logic unit
Here's the complete question below that clarifies what you need to do
<u>Explanation</u>:
"In this task, we will study the performance of public-key algorithms. Please prepare a file ( message.txt) that contains a 16-byte message. Please also generate an 1024-bit RSA public/private key pair. Then, do the following:
1)Encrypt message.txt using the public key; save the the output in message_enc.txt.
2)Decrypt message_enc.txt using the private key.
3)Encrypt message.txt using a 128-bit AES key.
<em><u>Compare the time spent on each of the above operations, and describe your observations. If an operation is too fast, you may want to repeat it for many times, i.e., 5000 times, and then take an average.</u></em>
<em><u> After you finish the above exercise, you can now use OpenSSL's speed command to do such a benchmarking. Please describe whether your observations are similar to those from the outputs of the speed command?</u></em>
Answer:
a. Utilization = 0.00039
b. Throughput = 50Kbps
Explanation:
<u>Given Data:</u>
Packet Size = L = 1kb = 8000 bits
Transmission Rate = R = 1 Gbps = 1 x 10⁹ bps
RTT = 20 msec
<u>To Find </u>
a. Sender Utilization = ?
b. Throughput = ?
Solution
a. Sender Utilization
<u>As Given </u>
Packet Size = L = 8000 bits
Transmission Rate = R = 1 Gbps = 1 x 10⁹ bps
Transmission Time = L/R = 8000 bits / 1 x 10⁹ bps = 8 micro-sec
Utilization = Transmission Time / RTT + Transmission Time
= 8 micro-sec/ 20 msec + 8 micro-sec
= 0.008 sec/ 20.008 sec
Utilization = 0.00039
b. Throughput
<u>As Given </u>
Packet Size = 1kb
RTT = 20ms = 20/100 sec = 0.02 sec
So,
Throughput = Packet Size/RTT = 1kb /0.02 = 50 kbps
So, the system has 50 kbps throughput over 1 Gbps Link.