AgNO₃ + NaCl = NaNO₃ + AgCl↓
c(AgNO₃)=0.04 mol/L
c(NaCl)=0.002 mol/L ⇒ n(AgCl)/L=0.002 mol/L
Ksp=[Ag⁺][Cl⁻]
the solubility of silver chloride
√Ksp=1.34*10⁻⁵ mol/L
n(AgCl)/L>√Ksp the precipitate of silver chloride is formed
<u>Answer:</u> The expression for equilibrium constant is
<u>Explanation:</u>
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as
For the general chemical equation:
The expression for is given as:
For the given chemical reaction:
The expression for is given as:
The concentration of solid is taken to be 0.
So, the expression for is given as:
Answer:
118.2 g H₂O
Explanation:
To find the mass of water, you need to (1) convert moles HNO₃ to moles H₂O (via mole-to-mole ratio from reaction coefficients) and then (2) convert moles H₂O to grams H₂O (via molar mass).
The molar mass of water can be found by combining the element's molar masses times their quantities. The ratios/conversions should be arranged in a way that allows for the cancellation of units (desired unit should be in the numerator).
Molar Mass (H₂O): 2(1 g/mol) + 16 g/mol
Molar Mass (H₂O): 18 g/mol
S + 6 HNO₃ ---> H₂SO₄ + 6 NO₂ + 2 H₂O
^ ^
19.7 moles HNO₃ 2 moles H₂O 18 g
-------------------------- x ----------------------- x --------------------- = 118.2 g H₂O
6 moles HNO₃ 1 mole H₂O
Answer:
Ice carving. It's still ice, it's not water, and it changes shape while not changing it's matter
Explanation:
At STP 32 g of O₂ would occupy by the same volume as 4 g of He
<h3>Further explanation</h3>
Complete question
At STP 32 g of O₂ would occupy by the same volume as:
- 4.0 g of He
- 8.0 g of CH₄
- 64 g of H₂
- 32 g of SO₂
Standard Conditions
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.
So the gas will have the same volume if the number of moles is the same
mol of 32 grams of O₂ :
<em>So mol of 4 g He = mol of 32 g O₂</em>