C. The difference<span>ce</span><span /><span> between the potential energy of the products and the potential energy of the reactants
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A granola bar states that it is 17.0% protein; each granola bar has a mass of 35.0 grams 5 bars need to consume to eat 29.7 grams of protein.
<h3 /><h3>What is protein?</h3>
Protein is a source of energy by which all humans and animals can do their work as it provide energy to the cells of the human and animal and important too.
A granola bar is source of protein contain 17.0% protein 35.0 grams each bar contain 5.2 gram protein 29.7 grams protein is in 5 bars of granola bar.
Therefore, granola bar states that it is 17.0% protein,each granola bar has a mass of 35.0 grams 5 bars need to consume to eat 29.7 grams of protein.
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You have already gotten the balanced equation. And the ratio of mol number of reactants and production is the ratio of coefficient. So there is 6.4/8*11=8.8 mol oxygen needed. The mass is 8.8*32=281.6 g.
Answer:
See explanation
Explanation:
Now we have, the graph attached.the stable disintegration product of C-14 is N-14.
Then;
Since the mass of C-14 originally present is 64g, at a time t= 17100 years, we will have;
N/No = (1/2)^t/t1/2
N = mass of C-14 at time t
No= mass C-14 originally present
t = time taken for N amount of C-14 to remain
No = mass of C-14 originally present
t1/2 = half life of C-14
N/64 = (1/2)^17,100/5730
N/64 = (1/2)^3
N/64 = 1/8
8N = 64
N = 8 g
I don’t have a picture but I can describe it to you.
The hydrogen that is attached at the tertiary position on the heptatriene (at the 7-methyl) would be very acidic, as removal would leave a positive charge that could be moved throughout the ring through resonance. This would mean that the three double bonds would be participating in resonance, and the deprotonated structure would be aromatic, thus making this favorable.
The hydrogen that is attached at the tertiary position on the pentadiene (5-methyl) would NOT be acidic, as removal would cause an antiaromatic structure.
Any other hydrogens would NOT be acidic. Those vinylic to their respective double bonds would seriously destabilize the double bond if removed, and hydrogens attached to the methyl group jutting off the ring have no incentive to leave the carbon.
Hope this helps!
