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vodka [1.7K]
3 years ago
15

What period is Pb in

Chemistry
1 answer:
ad-work [718]3 years ago
4 0

Pb (lead) is in the 6th period

(please give brainliest if this helped you)

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A mercury lamp emits radiation with a frequency of 5.62 x1024 Hz. Calculate the wavelength of
Nitella [24]

Answer:

wavelength = 0.534×10⁻¹⁶ m

Explanation:

Given data:

Frequency of wave = 5.62 ×10²⁴ Hz

Wavelength = ?

Solution:

Speed of photon = wavelength × frequency

wavelength = speed of photon / frequency

Now we will put the values in formula:

wavelength = 3×10⁸ m/s / 5.62 ×10²⁴ Hz

Hz = s⁻¹

wavelength = 3×10⁸ m/s / 5.62 ×10²⁴ s⁻¹

wavelength = 0.534×10⁻¹⁶ m

7 0
3 years ago
What is the answers pls need it before tomoz
QveST [7]
Metals consist of giant structure of atoms arranged in a regular pattern. The electrons in the outer shell of metal atoms are shared , and are free to move throughout the structure. Therefore the structure is formed by positive charged metal ions held together by a 'sea' of delocalised.  
5 0
3 years ago
Tetrahydrofuran (THF) is a common organic solvent with a boiling point of 339 K. Calculate the total energy (q) required to conv
poizon [28]

Explanation:

For the given reaction, the temperature of liquid will rise from 298 K to 339 K. Hence, heat energy required will be calculated as follows.

             Q_{1} = mC_{1} \Delta T_{1}

Putting the given values into the above equation as follows.

           Q_{1} = mC_{1} \Delta T_{1}

                      = 27.3 g \times 1.70 J/g K \times 41

                      = 1902.81 J

Now, conversion of liquid to vapor at the boiling point (339 K) is calculated as follows.

           Q_{2} = energy required = mL_{v}

    L_{v} = latent heat of vaporization

Therefor, calculate the value of energy required as follows.

             Q_{2} = mL_{v}

                         = 27.3 \times 444

                         = 12121.2 J

Therefore, rise in temperature of vapor from 339 K to 373 K is calculated as follows.

            Q_{3} = mC_{2} \Delta T_{2}

Value of C_{2} = 1.06 J/g,    \Delta T_{2} = (373 -339) K = 34 K

Hence, putting the given values into the above formula as follows.

             Q_{3} = mC_{2} \Delta T_{2}

                       = 27.3 g \times 1.06 J/g \times 34 K

                       = 983.892 J

Therefore, net heat required will be calculated as follows.

            Q = Q_{1} + Q_{2} + Q_{3}

                = 1902.81 J + 12121.2 J + 983.892 J

                = 15007.902 J

Thus, we can conclude that total energy (q) required to convert 27.3 g of THF at 298 K to a vapor at 373 K is 15007.902 J.

5 0
2 years ago
On the moon the acceleration due to gravity is 1.6 ms if an object has a mass on earth of 5.1kg what is its mass on the moon
Y_Kistochka [10]

Answer:

Mass on the moon is 5.1 kg.

Explanation:

Given mass on earth = 5.1 kg

acceleration due to gravity on moon = 1.6 ms⁻².

The mass on the moon does not change because mass is the quantity of matter in the body regardless of its volume or  of any forces acting on it.

Whereas the weight of the object changed.

Weight is the the force exerted on a body which is related to mass and expressed as W = mg.

W = weight of object   m = mass of object      and g = gravitational force

So\ in\ this\ case\ W\ =1.6\times\ 5.1\ =8.16N

N stands for newton unit of weight.

Thus mass of the object on moon is same as on earth which is 5.1 kg.

3 0
3 years ago
Determine the pH of 0.10 M NH3 solution. NH3 is a weak base with a Kb equal to 1.8x10-5 (round to the nearest whole number)
V125BC [204]

Answer:

11

Explanation:

I scoured across many websites to finally get this answer. And it is right, I just did the Instruction.

8 0
2 years ago
Read 2 more answers
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