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3 years ago

I need to know the two bottom ones

Mathematics

2 answers:

Gala2k [10]3 years ago

6 0

Answer:

1st one is 8 x 10 2nd one is 7 x 7

Step-by-step explanation:

Alexandra [31]3 years ago

6 0

4a. The answer is 10.

80 ÷ 8 = 10

4b. The answer is 7.

49 ÷ 7 = 7

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The water at the end of a pier was 28 meters deep at midnight. As the tide came in, the water depth increased at a rate of 0.012

Nastasia [14]

Answer:

0.012t + 28 = 30

Step-by-step explanation:

The depth starts at 28 meters. The amount of increase in t minutes will be 0.012t, so the total depth after t minutes is ...

0.012t +28

We want to find when that is equal to 30, so the appropriate equation is ...

0.012t +28 = 30

4 0

4 years ago

The equation h(t) = -16t² + 80t + 64 represented the height, in feet, of a potato t seconds after it has been launched.

Lyrx [107]

Answer:

Part A) The potato hit the ground at t=5.70 seconds (see the explanation)

Part B) The potato is 40 feet off the ground at the time t=5.28 seconds (see the explanation)

Step-by-step explanation:

we have

$h(t)=-16t^2+80t+64$

where

h(t) is the height of a potato in feet

t is the time in seconds

Part A) Write an equation that can be solved to find when the potato hits the ground. Then solve the equation

we know that

When the potato hit the ground, the value of h(t) must be equal to zero

For h(t)=0

$-16t^2+80t+64=0$

Solve the quadratic equation

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16t^2+80t+64=0$

$a=-16\\b=80\\c=64$

substitute in the formula

$t=\frac{-80\pm\sqrt{80^{2}-4(-16)(64)}} {2(-16)}$

$t=\frac{-80\pm\sqrt{10,496}} {-32}$

$t=\frac{-80+\sqrt{10,496}} {-32}=-0.70$

$t=\frac{-80-\sqrt{10,496}} {-32}=5.70$

therefore

The potato hit the ground at t=5.70 seconds

Part B) Write an equation that can be solved to find when the potato is 40 feet off the ground. Then solve the equation

For h(t)=40 ft

substitute in the quadratic equation

$-16t^2+80t+64=40$

$-16t^2+80t+24=0$

Solve the quadratic equation

we have

$a=-16\\b=80\\c=24$

substitute in the formula

$t=\frac{-80\pm\sqrt{80^{2}-4(-16)(24)}} {2(-16)}$

$t=\frac{-80\pm\sqrt{7,936}} {-32}$

$t=\frac{-80+\sqrt{7,936}} {-32}=-0.28$

$t=\frac{-80-\sqrt{7,936}} {-32}=5.28$

therefore

The potato is 40 feet off the ground at the time t=5.28 seconds

3 0

3 years ago

Determine whether the stated conclusion is valid based on the given information. Explain your reasoning.

Oduvanchick [21]

The answer is D. The law of detachment states that
"If P than Q. P."
In this case passing the bar exam is P and getting to practice law is Q. So if we know that Candice is allowed to practice law if she passes the bar exam and that she did pass the exam. The conclusion that Candice can now practice law is valid.

4 0

3 years ago

What is m∠Q ?

ddd [48]

Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.

Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A

Applying that here:

40^2 = 32^2 + 64^2 - 2(32)(64)cos Q

Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.

7 0

3 years ago

Read 2 more answers

What is the quotient of 3.12 x 108 and 2.6 x 105 expressed in scientific notation?

Gnoma [55]

Answer:

1.2 * 10^3

Step-by-step explanation:

3.12 * 10^8

=========

2.6 * 10^5

Start by doing 3.12 / 1.6 = 1.2 and that is the correct number of sig digs.

Now get the power on the 10. When dividing, the powers subtract.

10^(8 - 5)

10^ 3

The answer is 1.2 * 10^3

7 0

3 years ago