Answer:
<em>The distance between each picture is 37 inches</em>
Step-by-step explanation:
We must find the separation between each picture knowing the total space they will occupy and their individual dimensions. We are not told if the distance between them is the same as that from the borders, we'll assume it is.
The total width of the wall is 17 ft=17*12=204 inches
Two pictures are horizontal and occupy 20 inches each, for a total of 40 inches
One picture is vertical and occupy 16 inches. This means the total space occupied by the pictures is 40+16=56 inches.
The difference between the total width of the wall and this distance will be equally spaced. This difference is 204 - 56 = 148 inches
There are 4 spaces to be equally sized: two between the pictures and two to the borders. The separation of each must be 148/4=37 inches
The distance between each picture is 37 inches
1/5 of 120 is 24
1/3 of 120 is 40
3/10 of 120 is 36
120-24-40-36 =20
20/120 = 1/6
1/6 is covered with sprinkles.
From the information given you have:
1) Smaller diagonal of the kite: 16 inches
2) Larger diagonal of the kite: height of one triangle (h1) + height of the other triangle (h2)
3) Calculation of the height of the smaller triangle, h1:
10^2 = (16/2)^2 + (h1)^2 => h1 = √ [10^2 - 8^2] = 6
4) Calculation of the height of the larger triangle, h2
17^2 = (16/2)^2 + (h2)^2 => h2 = √[17^2 - 8^2] = 15
5) Larger diagonal = h1 + h2 = 6 + 15 = 21
Answer: 21 inches
Ans: 5*-3=-15
Step-by-step explanation:
The product of a positive and negative integer is negative.So, the product of 5 and -3 is -15
The answer is 108' because if you add 35+1 all you have to do is multiply that times 3 which is 36'×3=108'
