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slavikrds [6]
3 years ago
5

Solve the following equation algebraically:

Mathematics
1 answer:
Gre4nikov [31]3 years ago
8 0

Answer:

\boxed{\sf \ \ \ answer \ b. \ \ +5 \ \ \ }

Step-by-step explanation:

Hello

let's assume that we are looking for x >=0

4x^2=100  \dfrac{4x^2}{4}=x^2=\dfrac{100}{4}=25\\\sqrt{x^2}=25\\ |x| = 5  x = 5 \ or \ x=-5

Let's assume that we are looking for x>=0

so the correct answer is 5

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agasfer [191]

Answer:

102

Step-by-step explanation:

8 0
3 years ago
A group of 3 friends spends a total of $17.25 for brunch at a restaurant before tax and tip. Everyone orders the same thing: scr
liubo4ka [24]

Answer:

17.25/3 = 5.75

Step-by-step explanation:

You divide 17.25 by 3.

It equals 5.75. Each friend has 5.75 on spend on brunch.

Toast is $1. Orange Juice is $1.75. Eggs are $2.

Hope this helps.

3 0
3 years ago
757 divided by 68, the reamander, what is it?
egoroff_w [7]
68 can go into 757 11 times, the remainder would be 9

757÷68= 11 r 9 or 11 9/68
5 0
3 years ago
A raffle offers one $8000.00 prize, one $4000.00 prize, and five $1600.00 prizes. There are 5000 tickets sold at $5 each. Find t
Harman [31]

Answer:

The expectation is  E(1 )= -\$ 1

Step-by-step explanation:

From the question we are told that  

     The first offer is  x_1 =  \$ 8000

     The second offer is  x_2 =  \$ 4000

      The third offer is  \$ 1600

      The number of tickets is  n  =  5000

      The  price of each ticket is  p= \$ 5

Generally expectation is mathematically represented as

             E(x)=\sum  x *  P(X = x )

     P(X =  x_1  ) =  \frac{1}{5000}    given that they just offer one

    P(X =  x_1  ) = 0.0002    

 Now  

     P(X =  x_2  ) =  \frac{1}{5000}    given that they just offer one

     P(X =  x_2  ) = 0.0002    

 Now  

      P(X =  x_3  ) =  \frac{5}{5000}    given that they offer five

       P(X =  x_3  ) = 0.001

Hence the  expectation is evaluated as

       E(x)=8000 *  0.0002 + 4000 *  0.0002 + 1600 * 0.001

      E(x)=\$ 4

Now given that the price for a ticket is  \$ 5

The actual expectation when price of ticket has been removed is

      E(1 )= 4- 5

      E(1 )= -\$ 1

4 0
3 years ago
In the adjoining figure cross out dissimilar one and represent the set formed by following method​
Over [174]

Answer:

cross out 4

Step-by-step explanation:

explanation

3 0
2 years ago
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