Mr and Mrs jackson are having a family portraits taking with their son and daughter. the photographer wants to have two people s
it in the front and two people stand in the back. The jacksons have decided that they want to send a copy of their portrait to each of their relatives however they don't want any two portraits to be the same Mr Wilson has asked the photographer to place the family in as many different positions as possible.
If your question is how many positions are possible, then the answer is 24.
We find this by thinking of how many people can be in each spot. If there are 4 spots each person can stand (back left, back right, front left, front right), then there are 4 possible choice for the first spot (mom, dad, son, daughter), then 3 for the next spot (since 1 is already in a spot), then 2 options for the next spot, and then 1 option for the last spot. In other words, the answer is 4x3x2x1, or 4 factorial.
So, first let's change these numbers into decimal form: 3*0.1 + 4*0.01 + 8*0.001 ? 1.2 Multiply: 0.3 + 0.04 + 0.008 ? 1.2 0.348 < 1.2 One and two tenths is larger. Hopefully this is what you're asking, as this question is unclear
