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Alex777 [14]
3 years ago
15

Can a point have two different reflection images over the same line? Why or why not?

Mathematics
1 answer:
IrinaK [193]3 years ago
8 0
No a reflection is an exact copy just kinda flipped
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Megan has practiced the piano for 7.5 hours over the course of this week. She practices on Tuesdays, Thursdays, and Saturdays. H
gulaghasi [49]

Answer:

150

Step-by-step explanation:

you have three days and 7.5 so decide 7.5 by 3 it equals 2.5 which in minutes is 150

7 0
3 years ago
If I put 1500 into my savings account and 180 of interest at 4% simple interest how long was my money in my bank
stealth61 [152]

10,800 I think that's the answer


6 0
3 years ago
Please help me I tried to do it
anyanavicka [17]
You do 9x27=243 then take 2x31=62 add 243+62=305 then take 305 and subtract it from 28 305-28=277 
so if i did it right you should get n=277
8 0
3 years ago
If the original square had a side length of
irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas  in the attached figure N 3, and the trinomial is x^{2} +11x+28

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

Length=(x+4)\ in

width=(x+7)\ in

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas  in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

A1=(x)(x)=x^{2}\ in^2

A2=(4)(x)=4x\ in^2

A3=(x)(7)=7x\ in^2

A4=(4)(7)=28\ in^2

The total area of the second rectangle is the sum of the four areas

A=A1+A2+A3+A4

State the product of (x+4) and (x+7) as a trinomial

(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28

Part c) If the original square had a side length of  x = 2 inches, then what is the area of the  second rectangle?

we know that

The area of the second rectangle is equal to

A=A1+A2+A3+A4

For x=2 in

substitute the value of x in the area of each portion

A1=(2)(2)=4\ in^2

A2=(4)(2)=8\ in^2

A3=(2)(7)=14\ in^2

A4=(4)(7)=28\ in^2

A=4+8+14+28

A=54\ in^2

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

A(x)=x^{2} +11x+28

For x=2 in

substitute and solve for A(x)

A(2)=2^{2} +11(2)+28

A(2)=4 +22+28

A(2)=54\ in^2 ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0
3 years ago
Finding Distances from the Mean
Zepler [3.9K]

Answer:

13, 1, 0, 7, 7.

Step-by-step explanation:

if you were going to answer it then why is it here

7 0
3 years ago
Read 2 more answers
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