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3 years ago

Can a point have two different reflection images over the same line? Why or why not?

Mathematics

1 answer:

IrinaK [193]3 years ago

8 0

No a reflection is an exact copy just kinda flipped

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If you help me I will help you just message me

Leviafan [203]

Answer:

i hel32hhfkhf2ehkf e2k fe2kn fkne2 fe2fn3 3 3juur3jke

Step-by-step explanation:

3 0

3 years ago

Help... Best to explain will get brainliest

fenix001 [56]

Answer:

3m + 2 ≤ 20

Step-by-step explanation:

Since they only have $20 and CANNOT go over it, the inequality would be ≤ 20

3m + 2 ≤ 20

8 0

3 years ago

Read 2 more answers

Which number would fit in?

almond37 [142]

Answer:

Answer is 3/6th

Step-by-step explanation:

Because 2/4 is a half so what is 3 as a half of a fraction which is

3/6

5 0

2 years ago

Read 2 more answers

Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.

charle [14.2K]

ANSWER

See below

EXPLANATION

Given

$f(x) = \frac{ {x}- 9 }{x + 5}$

and

$g(x) = \frac{ - 5x - 9}{x - 1}$

$(f \circ \: g)(x)= \frac{ (\frac{ - 5x - 9}{x - 1})- 9 }{(\frac{ - 5x - 9}{x - 1} )+ 5}$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9(x - 1)}{x - 1}}{\frac{ - 5x - 9 + 5(x - 1)}{x - 1} }$

Expand:

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9x + 9}{x - 1}}{\frac{ - 5x - 9 + 5x - 5}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9x + 9 - 9}{x - 1}}{\frac{ - 5x + 5x - 5 - 9}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 14x }{x - 1}}{\frac{ -14}{x - 1} }$

Since the denominators are the same, they will cancel out,

$(f \circ \: g)(x)= \frac{ - 14x}{ - 14} = x$

8 0

2 years ago

Domain and range of the inequality y<√x+3 +1

Margaret [11]

The domain of the given inequality is y>1.

<h3>What is Inequality?</h3>

An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions.

Here, given inequality:

y < $\sqrt{x+3}+1$

Related equation:

y = $\sqrt{x+3}+1$

The equation defined as,

x+3 > 0

x > -3

In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.

So, the domain of the given inequality is x>-3.

We know that,

$\sqrt{x+3} \geq 0$

adding 1 on both sides, we get

$\sqrt{x+3} + 1 \geq 1$

y ≥ 1

The points on the boundary line are not included in the solution set. Thus, 1 is not included in the range.

Thus, the domain of the given inequality is y>1.

Learn more about Inequality from:

brainly.com/question/20383699

#SPJ1

6 0

1 year ago