If he ran 35 meters in 10 seconds, how many meters did he run in a second?
35m=10s
? =1
1/10*35m=3.5m
Therefore he ran 3.5 meters in a second.
Answer:
HIIIIIIII NMMNDKK F.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let the integer be 6 for even and 7 for odd (say)
For 6, we divide by 2, now get 3. Now we multiply by 3 and add 1 to get 10. Now since 10 is even divide by 5, now multiply by 3 and add 1 to get 16. Now divide by 2 again by 2 again by 2 again by 2 till we get rid of even numbers.
The result is 1, so multiply by 3 and add 1 we get 4 now divide 2 times by 2 to get 1, thus this result now again repeats after 2 times.
Say if we select off number 3, multiply by 3 and add 1 to get 10 now divide by 5, now repeat the same process as above for 5 until we get 1 and it gets repeated every third time.
Thus whether odd or even after some processes, we get 1 and the process again and again returns to 1.
Answer:
25
Step-by-step explanation:
x^2=24^2+7^2
=576+49
=625
x=25
Answer:
The answer to this question would be B:
Based on the question, since the weight of the weight plates are 20 lbs, this would be represented by the 20x in the function. As well, the 5 lb barbell would be represented by the 5 in the function. The range of the function is determined by the amount of weight plates are added. So if I added one weight plate the equation would equal, f(x) = 20(1) + 5 = 25. This continues on the more and more weight plates you add.
Hope this reached you well :)
Step-by-step explanation:
20 = weight of the weight plates
x = amount of weight plates.
5 = weight of the barbell
f(x) = 20(0) + 5 = 5
f(x) = 20(1) + 5 = 25
f(x) = 20(2) + 5 = 45
f(x) = 20(3) + 5 = 65
f(x) = 20(4) + 5 = 85
