3 years ago

Help please, sorry y'all for the spam. thank you in advance!

Mathematics

1 answer:

ehidna [41]3 years ago

7 0

Angle ADB is 43.
If you need the explanation just ask

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Yesterday, Jed's bank account balance was –$26.34. He deposited some money into his account so that the balance is now $42.18.

omeli [17]

It's D $68.52 due to the act that 42.18 + 26.34= $68.52

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3 years ago

Question 37

Genrish500 [490]

It’s 56689 + the power of everything is 25 round it up

7 0

3 years ago

I need help please!

Sophie [7]

Answer/Step-by-step explanation:

Area of trapezium = ½*(AD + BC)*AB

Area = 42 cm²

AD = (x + 8) cm

BC = (x + 5) cm

AB = x cm

Plug in the values into the equation

42 = ½((x + 8) + (x + 5))*x

42 = ½((x + 8 + x + 5)*x

42 = ½(2x + 13)*x

Multiply both sides by 2

42*2 = (2x + 13)*x

84 = 2x² + 13x

2x² + 13x = 84

Subtract both sides by 84

2x² + 13x - 84 = 0

4 0

3 years ago

Find an equivalent 100/25

Varvara68 [4.7K]

Answer:

100/25 = 4

so an equivalent would be 12/3

6 0

3 years ago

Read 2 more answers

In the isosceles △ABC m∠ACB=120° and AD is an altitude to leg BC . What is the distance from D to base AB , if CD=4cm?

7nadin3 [17]

Correct answer is: distance from D to AB is 6cm

Solution:-

Let us assume E is the altitude drawn from D to AB.

Given that m∠ACB=120° and ABC is isosceles which means

m∠ABC=m∠BAC = $\frac{180-120}{2}=30$

And AC= BC

Let AC=BC=x

Then from ΔACD , cos(∠ACD) = $\frac{DC}{AC} =\frac{4}{x}$

Since DCB is a straight line m∠ACD+m∠ACB =180

m∠ACD = 180-m∠ACB = 60

Hence $cos(60)=\frac{4}{x}$

$x=\frac{4}{cos60}= 8$

Now let us consider ΔBDE, sin(∠DBE) = $\frac{DE}{DB} =\frac{DE}{DA+AB} = \frac{DE}{4+8}$

$DE = 12sin(30) = 6cm$

7 0

3 years ago

Help please, sorry y'all for the spam. thank you in advance! ​

Help please, sorry y'all for the spam. thank you in advance!