Answer:
1.
P(E1)=P(E2)=P(E3)=P(E4)=P(E5= )1/5
2.
P(E1)=0.4
P(E2)= 0.26
P(E3)=0.34
3.
No the probability assignments are invalid
Step-by-step explanation:
1
Total number of possible outcomes = 5
<u>Equation (4.3)</u>
0< P(Ei)<1
<u>Equation (4.4)</u>
P(E1) + P(E2) +........+P(En)=1
As the outcomes are equally likely therefore,
Probability for each outcome= P(Ei) = 1/5
2
Total number of outcomes = 50
Outcomes for event E(1)= 20
Outcomes or event E(2)= 13
Outcomes or event E(3) = 17
P(Ei)= (number of outcomes for event Ei/ Total number of outcomes)
P(E1)=20/50=0.4
P(E2)= 13/50=0.26
P(E3)=17/50=0.34
3
P(E1) .10,
P(E2) .15,
P(E3) .40,
P(E4) .20
0.1 +0.15+0.40+0.20=0.85<1
According to equation (4.4) the probability assignments are invalid as the sum of probabilities for all outcomes must be equal to 1.