The value of k such that (x-5) divides the polynomial p(x)= x^3-6x^2+kx+30 exactly,is
1 answer:
Answer:
k = - 1
Step-by-step explanation:
If (x - 5) is a factor of p(x) then p(5) = 0
p(5) = 5³ - 6(5)² + 5k + 30 = 0 , that is
125 - 150 + 5k + 30 = 0
5 + 5k = 0 ( subtract 5 from both sides )
5k = - 5 ( divide both sides by 5 )
k = - 1
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