Let "x" be a substitute for "a number"
1/3(x)=x-12 Multiply by 3
x=3x-36 Get n onto the same side of the equation
2x=36 Divide by 2
x=18
That's your answer.
<span>a) Differentiate both sides of lnq − 3lnp + 0.003p=7 with respect to p, keeping in mind that q is a function of p and so using the Chain Rule to differentiate any functions of q:
(1/q)(dq/dp) − 3/p + 0.003 = 0
dq/dp = (3/p − 0.003)q.
So E(p) = dq/dp (p/q) = (3/p − 0.003)(q)(p/q) = (3/p − 0.003)p = 3 − 0.003p.
b) The revenue is pq.
Note that (d/dp) of pq = q + p dq/dp = q[1 + dq/dp (p/q)] = q(1 + E(p)), which is zero when E(p) = −1. Therefore, to maximize revenue, set E(p) = −1:
3 − 0.003p = −1
0.003p = 4
p = 4/0.003 = 4000/3 = 1333.33</span>
Answer:
Step-by-step explanation:
10-h
11-A
12-g
13-a
14-f
Mark as brainlest please
Answer:
D
Step-by-step explanation:
try all of them
Answer:
the markup percentage is 66.67%
Step-by-step explanation:
The computation of the percent of markup based on cost is shown below:
= (Selling price - paid price) ÷ (paid price)
= ($15 - $9) ÷ ($9)
= 66.67%
By taking the difference of the selling price & paid price and then divided it by paid price we can get the percentage of markup
Hence, the markup percentage is 66.67%
