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Mrac [35]
4 years ago
6

The current in a circuit is tripled by connecting a 580 resistor in parallel with the resistance of the circuit. Determine the r

esistance of the circuit in the absence of the 580 resistor.
Physics
1 answer:
Anika [276]4 years ago
5 0

Answer:

1160 ohm

Explanation:

We are given that

R'=580 ohm

Current=3 I

We have to find the resistance of the circuit.

Let R be the resistance of circuit.

In parallel

\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}

Using the formula

\frac{1}{R_{eq}}=\frac{1}{580}+\frac{1}{R}=\frac{580+R}{580R}

R_{eq}=\frac{580R}{580+R}

In parallel combination,Potential difference across each resistance remains same.

V=IR

Using the formula

IR=3IR_{eq}

IR=3I\times \frac{580R}{580+R}

580+R=3\times 580=1740

R=1740-580=1160\Omega

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A student measures the mass of a 1.0 kg standard bar. He obtains measurements of 0.77 kg, 0.78 kg, and 0.79 kg. Which describes
Vadim26 [7]

Complete question

A student measures the mass of a 1.0 kg standard bar. He obtains measurements of 0.77 kg, 0.78 kg, and 0.79 kg. Which describes his measurements

a)precise but not accurate

b)accurate but not precise

c)neither precise nor accurate

d)both precise and accurate

Answer:

The measurement is precise but not accurate

Explanation:

A measurement can either be precise or accurate.

  • A Precise measurement describes how close the measured values are to each other.
  • An accurate measurement describes how close a measured value is to the true value.

In this question, the measured values (0.77 kg, 0.78 kg and 0.79 kg) are far from the true value (1.0 kg), therefore the measurement is not accurate.

However, the measured values (0.77 kg, 0.78 kg and 0.79 kg) are close to each other, therefore the measurement is precise.

Therefore the correct option is 'a' the measurement is precise but not accurate

4 0
3 years ago
The presence of dwarf galaxies around the Milky Way supports what picture of our galaxy’s formation?
elena-14-01-66 [18.8K]

Answer:

The presence of dwarf galaxies around the Milky Way supports what picture that our galaxy was formed by a coming together or combination of smaller systems

4 0
4 years ago
Example of what happens to particles when their kinetic energy decreases?
Ann [662]

Explanation:

<h2>When we decrease the temperature, less heat energy is supplied to the atoms, and so their average kinetic energy decreases. When they enter a phase transition, such as freezing from a liquid to a solid, the temperature is not decreasing or increasing, and stays constant</h2>
6 0
3 years ago
Read 2 more answers
If the prism is surrounded by a fluid, what is the maximum index of refraction of the fluid that will still cause total internal
larisa86 [58]

Answer:

n₁ > n₂.

prisms are made of glass with refractive index n₂ = 1.50, so the fluid that surrounds the prism must have an index n₁> 1.50

Explanation:

Total internal reflection occurs when the refractive index of the incident medium the light is greater than the medium to which the light is refracted, let's use the refraction equation

                 n₁ sin θ₁ = n₂ sin  θ₂

the incident medium is 1, at the limit point where refraction occurs is when the angle in the refracted medium is 90º, so sin θ₂ = 1

                 n₁ sin θ₁ = n₂

                 sin θ₁ = n₂ / n₁

We mean that this equation is defined only for n₁ > n₂.

In our case, for the total internal reflection to occur, the refractive incidence of the medium must be greater than the index of refraction of the prism.

In general, prisms are made of glass with refractive index n₂ = 1.50, so the fluid that surrounds the prism must have an index n₁> 1.50

6 0
3 years ago
The average marathon runner can complete the 42.2-km distance of the marathon in 3 h and 30 min. If the runner's mass is 85 kg,
Semenov [28]

Answer:

the runner's average kinetic energy during the run is 476.96 J.

Explanation:

Given;

mass of the runner, m = 85 kg

distance covered by the runner, d = 42.2 km = 42,200 m

time to complete the race, t = 3 hours 30 mins = (3 x 3600s) + (30 x 60s)

                                                                               = 12,600 s

The speed of the runner, v = d/t

                                          v = 42,200 / 12,600

                                          v = 3.35 m/s

The runner's average kinetic energy during the run is calculated as;

K.E = ¹/₂mv²

K.E = ¹/₂ × 85 × (3.35)²

K.E = 476.96 J

Therefore, the runner's average kinetic energy during the run is 476.96 J.

5 0
3 years ago
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