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Hoochie [10]
3 years ago
6

If the prism is surrounded by a fluid, what is the maximum index of refraction of the fluid that will still cause total internal

reflection
Physics
1 answer:
larisa86 [58]3 years ago
6 0

Answer:

n₁ > n₂.

prisms are made of glass with refractive index n₂ = 1.50, so the fluid that surrounds the prism must have an index n₁> 1.50

Explanation:

Total internal reflection occurs when the refractive index of the incident medium the light is greater than the medium to which the light is refracted, let's use the refraction equation

                 n₁ sin θ₁ = n₂ sin  θ₂

the incident medium is 1, at the limit point where refraction occurs is when the angle in the refracted medium is 90º, so sin θ₂ = 1

                 n₁ sin θ₁ = n₂

                 sin θ₁ = n₂ / n₁

We mean that this equation is defined only for n₁ > n₂.

In our case, for the total internal reflection to occur, the refractive incidence of the medium must be greater than the index of refraction of the prism.

In general, prisms are made of glass with refractive index n₂ = 1.50, so the fluid that surrounds the prism must have an index n₁> 1.50

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Explanation:

We can solve this problem by using the law of conservation of energy.

In absence of frictional effect, the mechanical energy of the apple must be conserved during the fall. So we can write:

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U_i is the initial potential energy, at the top

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K_f is the final kinetic energy, at the bottom

By explicing the potential energy, we can rewrite the equation as:

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Two objects of the same size are both perfect blackbodies. One has a temperature of 3000 K, so its frequency of maximum emission
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Answer:

a) The colder body (3000k), b) hearter body c) 12000K body

Explanation:

This exercise should know the power emitted by the objects and the distribution of this emission in the energy spectrum, for this we will use Stefan's laws and that of Wien's displacement

Stefan's Law                     P = σ A e T⁴

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As they are perfect black bodies e = 1, they also indicate that they have the same area

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Let's calculate the maximum emission wavelength

Body 1

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a) The colder body (3000k) emits more light in the infrared, since the emission of the hot body is at a minimum (emission tail)

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c) The emission of the hottest 12000K body is mainly in UV

d) The hottest body emits more energy in UV and visible

e) No body has greater emission in all zones

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