All categories

3 years ago

Solve. open parentheses square root of 7 close parentheses to the 6 x power = 49x-6

2 answers:

7 0

The equation is(√7)^6x = 49x - 6
This equation can be solved by iteration.

Rearranging:
x = ( (√7)^6x + 6 )/49

We start with a value of x = 3.
This value can be substituted to the right side and new value of x can be obtained. This new value can be substituted again to the right side of the equation and another new value for x is obtained. This process is repeated until the old and new values of x are the same.

The result is,x = 0.5

Nata [24]3 years ago

3 0

Is this the equation?
$(\sqrt{7^}}) ^6x} = 49 ^{x-6}$

First is to transform the two sides of the equation to have like bases.
$7^{ \frac{6x}{2} } = 7^{2(x-6)}$

Simplifying would result to:
$7^{3x}} = 7^{2x-12}$

Equating the exponents:
3x =2x+12
x= 12

If you would want to solve for x then x=12.

You might be interested in

All athletes at the Olympic Games (OG) are tested for performance-enhancing steroid drug use. The basic Anabolic Steroid Test (A

Semenov [28]

Answer:

a ) the probability of using steroids and having a negative test is 0.5%

b) The probability of testing positive is 6.4%

c) The probability of not using steroids, given that the test is negative is 99.47%

d) No, they are not statistically indepent.

e) The probability that the athlete will either use steroids or test positive is 6.9%

Step-by-step explanation:

Let A be the event that the test result is positive and B the event that the athlete uses Steroids. We are given the following

$P(A|B) = 90%, P(A|B^c) = 2%, P(B) = 5%$

From which we deduce that

$P(A^c|B) = 10%, P(B^c) = 95%$

a) We are asked for the probability $P(A^c\cap B)$ . REcall the conditional probability formula that, given two events C,D the conditional probability $P(C|D) = \frac{P(C\cap D)}{P(D)}$ . Then we have that

$P(A^c\cap B) = P(A^c|B)P(B) = 10\% \cdot 5\%=0.5\%$ .

b) We are asked for the probability P(A). We can use the fact that given two mutually exclusive events(that is, whose intersection is empty) A,B the probability P(C) of an event is given by $P(C) = P(C|A)P(A)+P(C|B)P(B)$ . Then

$P(A) = P(A|B)P(B)+P(A|B^c)P(B^c) = 90\%\cdot5\% + 2\% \cdot 95% = 6.4\%$

c) We are asked for the probability P(B^c|A^c). Recall that $P(A|B) = \frac{P(B|A)P(A)}{P(B)}$ . Then

$P(B^c|A^c) = \frac{P(A^c|B^c)P(B^c)}{P(A^c)}= \frac{P(A^c|B^c)P(B^c)}{1-P(A)}= \frac{(1-P(A|B^c))P(B^c)}{1-P(A)}=\frac{98\%\cdot 95\%}{1-6.4\%}= 99.47\%$

d) We say that two events A,B are statistically indepent if P(A|B) = P(A). Note that from point B the probability of testing negative is 1- 6.4% = 93.6%. Since 93.6% is different from 99.47% this means that testing positive and using steroids are not statistically independent.

e) We are asked for the probability $P(A\cup B)$ . We use the following

$P(A\cupB) = P(A)+P(B)-P(A\cap B) = P(A) +P(B)-P(A|B)P(B) = 6.4\%+5\%-90\%\cdot 5\%=6.9\%$

4 0

4 years ago

Help please?<br><br> (it’s y=mx+b stuff)

Gelneren [198K]

Answer:

5. C

6. A

Step-by-step explanation:

To find the answer, plug in the x- and y-values into each equation. When the equation comes to be true that is your answer.

So for question 5, you plug -5 into the x and 13 into the y for each equation. The first equation will give you an answer of 13 = -7, which isn't true.

The second will give you 13 = 7, so you keep going.

The third gives you 13 = 13, which is true, so that one must be the answer.

Do this for every question and it will give you the answer.

5 0

3 years ago

EXPERT HELP: DON'T GUESS AND EXPLAIN THE ANSWER

AysviL [449]

Answer:

Step-by-step explanation:

Well for one b is less than a just look at it.

7 0

3 years ago

Read 2 more answers

Which statement is true about the equations –3x + 4y = 12 and x – y = 1?

Anastaziya [24]

The answer is the 4th choice

4 0

3 years ago

First, work out the difference (decrease) between the two numbers you are comparing. Next, divide the decrease by the original n

mariarad [96]

Answer:18

Step-by-step explanation:

its

6 0

3 years ago