Question

Use a graphing calculator to sketch the graph of the quadratic equation, and then give the coordinates for the x-

Answer 1

Given:

The quadratic equation is

$y=6x^2-15x+6$

To find:

The x-intercepts of the given equation.

Solution:

We have,

$y=6x^2-15x+6$

Splitting the middle term, we get

$y=6x^2-12x-3x+6$

$y=6x(x-2)-3(x-2)$

$y=(x-2)(6x-3)$

For x-intercepts, y=0.

$(x-2)(6x-3)=0$

Using zero product property, we get

$x-2=0\text{ and }6x-3=0$

$x=2\text{ and }6x=3$

$x=2\text{ and }x=\dfrac{3}{6}$

$x=2\text{ and }x=0.5$

So, the x-intercepts are (0.5,0) and (2,0).

Therefore, the correct option is a.