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Alex
4 years ago
12

(07.06 MC) The graph of f(x) = 2x + 1 is shown below. Explain how to find the average rate of change between x = 0 and x = 3.

Mathematics
2 answers:
xxMikexx [17]4 years ago
7 0

Answer:

2.

Step-by-step explanation:

We have been given the formula of a function f(x)=2x+1. We are asked to find the average rate of change of the given function between x=0 and x=3.

To find the average rate of change we will use formula:

\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}

Upon substituting our given values in above formula we will get,

\text{Average rate of change}=\frac{f(3)-f(0)}{3-0}

\text{Average rate of change}=\frac{2\cdot 3+1-(2\cdot 0+1)}{3-0}

\text{Average rate of change}=\frac{6+1-(0+1)}{3}

\text{Average rate of change}=\frac{6}{3}

\text{Average rate of change}=2

Therefore, the average rate of change for our given function between x=0 and x=3 is 2.

Tju [1.3M]4 years ago
5 0
Find the rate of change at x=0 and at x=3, then find the average of those values.

f(0) = 2(0) + 1 = 1
f(3) - 2(3) + 1 = 7
 
\frac{f(0)+f(3)}{2} =  \frac{1 + 7}{2} =  \frac{8}{2} = 4

Answer: 4


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IRINA_888 [86]

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i wanna say 12.8, 13.3, 13.8

im not sure though, i hope this helps

7 0
3 years ago
I need help with question number three can someone help me please I need to get this right
DENIUS [597]

Answer:

False

Step-by-step explanation:

The included side in ASA is inside between the angles being used

4 0
4 years ago
If you answer this I will give you brainiest!
Helga [31]

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1 54 2 132 3 334.58 4 103.18

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Translate the algebraic expression and simplify if possible.
tamaranim1 [39]
-2/(a+b)
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4 0
3 years ago
A basketball gymnasium is 25 meters high, 80 meters wide and 200 meters long. We want to connect two strings, one from each of t
Rudiy27

Answer:

a) the centre is at (12.5 m, 40 m , 100 m ) with respect to our position

b) the length of the strings S will be 216.85 m

c) the angle that is formed by the strings is  1.23 rad

Step-by-step explanation:

assuming that we stand on one of the corners on the floor , so our coordinates are (0,0,0)  , then the coordinates of the center of the gymnasium   are found through

x center = (25 + 0)/2 = 12.5 m

y center = (80+ 0)/2 = 40 m

z center = (200+ 0)/2 = 100 m

then the centre is at (12.5 m, 40 m , 100 m ) with respect to our position

b) the length of the strings S will be the modulus of the vector that points from our position to the diagonally opposite corners

|S| = √(25²+80²+200²) = 216.85 m

c) the angle can be found through the dot product of the vectors that represent the strings S₁ and S₂

S₁ =(25,80,10)

S₂ =(-25,80,100)

then

S₁*S₂ = 25*(-25) +80*80 + 100*100 = 15775

but also

S₁*S₂ = |S₁||S₂| cos θ = |S|² * cos θ

S₁*S₂ =  |S|² * cos θ

cos θ= S₁*S₂/|S|²

θ= cos ⁻¹ ( S₁*S₂/|S|² ) = cos ⁻¹ [15775/(25²+80²+200²)] = 1.23 rad

7 0
3 years ago
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