In 1, t<span>here are 6 outcomes for each die, so for three dice, the total combination is 6 x 6 x 6 = 216 outcomes. Hence, t</span><span>he probability of any individual outcome is 1/216 </span>
The outcomes that will add up to 6 are
<span>1+1+4 </span>
<span>1+4+1 </span>
<span>4+1+1 </span>
<span>1+2+3 </span>
<span>1+3+2 </span>
<span>2+1+3 </span>
<span>2+3+1 </span>
<span>3+1+2 </span>
<span>3+2+1 </span>
<span>2+2+2 </span>
<span>Hence the probability is </span><span>10/216 </span>
In 3, the minimum sum of the three dice is 3. so we start with this
<span>P(n = 3) </span>
<span>1+1+1 ; </span><span>1/216 </span>
<span>P(n = 4) </span>
<span>1+1+2 </span>
<span>1+2+1 </span>
<span>2+1+1 ; </span><span>3/216 </span>
<span>P(n = 5) </span>
<span>1+1+3 </span>
<span>1+3+1 </span>
<span>3+1+1 </span>
<span>1+2+2 </span>
<span>2+1+2 </span>
<span>2+2+1; </span><span>6/216
The sum in 3 is 10/216 or 5/108</span>
Step-by-step explanation:
The Answer for the above question is
The four integers are 1,2,5,10. And Sum of the four integers is 18 .
<u>Method : </u>
Product of four different positive integers is 100 .
<u>First</u> of all lets break the number "100"
⇒ 100 = 50*2
⇒ 100 = 25 * 2 * 2
⇒ 100 = 5 * 5 * 2 * 2
But here we get the same integers 2 and 5 and we want different positive integers . So hereby merge 5 * 2 which is 10.
Let's get to the possible combination -
After merging 5*2 = 10 we get the answer as -
⇒ 100 = 1 * 2 * 5 * 10
Here, we have 1, 2, 5, 10. these are the positive integers whose product gives 100 .
Sum of these products is -
⇒ Sum = 1 + 2 + 5 + 10
⇒ Sum = 18 .
Sum of these four Integers is 18.