Let x be the number of running plays
Y be the number of
passing plays
Since the total plays is 110
X + y = 110
And total yard is 378
3x + 7y = 378
Using the first equation
X = 110 – y and substitute to the 2nd equation
3(110 – y) + 7y = 378
And solve for y
Y = 12
Substitute to eqution 1
X = 110 – 12 = 98
20.25-9(1/2)+11
=20.25-4.5+11
=26.75
Answer: The nth term of a geometric progression is Tn = ar^(n-1)
A. 12
B. 3.6
C. -3/4
D. 0.6
Step-by-step explanation:
The nth term of a geometric progression is Tn = ar^(n-1)
Where Tn= nth term
a = first term
r = common ratio
n = number
A. a6 = (2*6) = 12
B. a6 = (0.6*6) = 3.6
C. a6 = (-1/8*6) = -3/4
D. a6 = (0.1*6) = 0.6
Answer:
2
Step-by-step explanation:
