Suppose you add x liters of pure water to the 10 L of 25% acid solution. The new solution's volume is x + 10 L. Each L of pure water contributes no acid, while the starting solution contains 2.5 L of acid. So in the new solution, you end up with a concentration of (2.5 L)/(x + 10 L), and you want this concentration to be 10%. So we have

and so you would need to add 15 L of pure water to get the desired concentration of acid.
Step-by-step explanation:
2^3 X 3^-4 X 5^2 / (2x5)^2 X 2 X 3^2 X 3^-6
I will simply the expression on the RHS if the bracket first
2^2 X 5^2 X 2 X 3^2 X 3^-6
= 2^3 X 3^-4 X 5^2
So, putting them together
Both sides have th same expression
They cancel out each other
Answer : 1
Answer:
Step-by-step explanation:
Nyu thanks, I can't be helped either
Speed = distance over time.
300/5 is the same as 300÷5, which is 60