Answer:
156
Step-by-step explanation:
s8 = n/2 [2t + (n-1)(d)]
= 8/2 [2(2) + (8-1)(5)]
= 4 [4 + (7)(5)]
= 4 (4 + 35)
= 4 (39)
= 156
Answer:
The area of the square adjacent to the third side of the triangle is 11 units²
Step-by-step explanation:
We are given the area of two squares, one being 33 units² the other 44 units². A square is present with all sides being equal, and hence the length of the square present with an area of 33 units² say, should be x² = 33 - if x = the length of one side. Let's make it so that this side belongs to the side of the triangle, to our convenience,
x² = 33,
x = 
.... this is the length of the square, but also a leg of the triangle. Let's calculate the length of the square present with an area of 44 units². This would also be the hypotenuse of the triangle.
x² = 44,
x = 
.... applying pythagorean theorem we should receive the length of a side of the unknown square area. By taking this length to the power of two, we can calculate the square's area, and hence get our solution.
Let x = the length of the side of the unknown square's area -
= 
+ 
,
x = 
... And squared is 11, making the area of this square 11 units².
Answer:
Answer is C
Step-by-step explanation:
because you take three you divide both sides then the answer it will be 4
Answer:
Volume of the liquid left in the container will be 80 ml.
Step-by-step explanation:
Two containers A and B having equal volumes of the liquid has been shown in the figure attached.
Let the volume of the liquid in each container = x ml
120 ml of the liquid was poured in container B from container A.
Volume of liquid in container B = 4 × Volume of the liquid in container A
x + 120 = 4(x - 120)
x + 120 = 4x - 480
4x - x = 480 + 120
3x = 600
x = 200 ml
Volume of the liquid left in container A = 200 - 120
= 80 ml
Therefore, volume of the liquid left in the container A will be 80 ml.
