Why is6-8 greater than 5-8 but less than 7-8?

How do i solve this step by step??

Levart [38]

Answer:

x = 30

Step-by-step explanation:

well the two agnles are congruent so they have to equal the same angle

x+ 90 = 4x

solve for x bye subtracting x from 90

90 = 3x slove by dividing 90 by 3 getting x alone

90/3 = x

3 0

2 years ago

You are working on an urban planning project assessing the growth of a city. Five years ago, the population was 134,785 The curr

Firdavs [7]

To calculate growth rate, start by subtracting the past value from the current value. Then, divide that number by the past value. Finally, multiply your answer by 100 to express it as a percentage.

<u>Explanation:</u>

The "population growth rate" is the rate at which the number of individuals in a population increases in a given time period, expressed as a fraction of the initial population. Population growth is based on four fundamental factors: birth rate, death rate, immigration, and emigration.

Annual Growth Rate of Population refers to the rate at which the number of individuals in a given popular increase over a year, expressed as a fraction of the initial popular of the previous years. The annual percentage growth rate of population is the percent growth divided by the number of years.

8 0

2 years ago

Expand: f(x)= x^4- x^3+x^2+x-

emmainna [20.7K]

F(x) = x (x^3 - x^2 + x + 1)

6 0

2 years ago

The girl scouts are planning to sell chocolate cookies at $10.50 and lollipops at $2.50 each. They were able to collect $350 in

12345 [234]

Answer: 389

Step-by-step explanation: well if there is lollipops for $2.50 each and they sold thrice as many lollipops then they have sold 7.5 of the lollipops and if you sell thrice of the cookies then that will be 31.5 and if you add 7.5 and 31.5 that will be 39 so the real answer is 389.

5 0

3 years ago

A random sample of 25 ACME employees showed the average number of vacation days taken during the year is 18.3 days with a standa

Norma-Jean [14]

Answer:

a) Null hypothesis: $\mu \leq 15$

Alternative hypothesis: $\mu > 15$

b) $df=n-1=25-1=24$

For this case the p value is given $p_v = 0.0392$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 5% of signficance.

c) Type I error, also known as a “false positive” is the error of rejecting a null hypothesis when it is actually true. Can be interpreted as the error of no reject an alternative hypothesis when the results can be attributed not to the reality.

So for this case a type I of error would be reject the hypothesis that the true mean is less or equal than 15 and is actually true.

Step-by-step explanation:

Data given and notation

$\bar X=18.3$ represent the sample mean

$s=3.72$ represent the sample standard deviation

$n=25$ sample size

$\mu_o =15$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Part a: State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean for vacation days is higher than 15, the system of hypothesis would be:

Null hypothesis: $\mu \leq 15$

Alternative hypothesis: $\mu > 15$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Part b: P-value and conclusion

The first step is calculate the degrees of freedom, on this case:

$df=n-1=25-1=24$

For this case the p value is given $p_v = 0.0392$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 5% of signficance.

Part c

Type I error, also known as a “false positive” is the error of rejecting a null hypothesis when it is actually true. Can be interpreted as the error of no reject an alternative hypothesis when the results can be attributed not to the reality.

So for this case a type I of error would be reject the hypothesis that the true mean is less or equal than 15 and is actually true.

3 0

2 years ago