Answers:
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Explanation:
7+6 = 13. Divide this over 5 to get 13/5 = 2 remainder 3. The quotient 2 is something we don't care about. <u>We only worry about the remainder</u>. Therefore 7+6 = 3 (mod 5)
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2+1 = 3 (mod 5) for similar reasoning as above. 3/5 = 0 remainder 3.
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20 = 9 (mod 11) since 20/11 = 1 remainder 9. Imagine you had 20 cookies and 11 friends. Each friend would get 1 whole cookie (quotient) and there could be 9 left over (remainder).
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35/11 = 3 remainder 2
Or you could use repeated subtraction like so to find the remainder
35-11 = 24
24-11 = 13
13-11 = 2
The last result (2) is smaller than 11, so we stop here and this is the remainder.
Therefore, 35 = 2 (mod 11)
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Here's another way to think of it. Consider you have $35 in your pocket. Let's say a store is selling trinkets for $11 each. We can pose these key questions:
- What is the most number of trinkets you can buy?
- If you buy that max amount, how much will you have left over?
The answer to the first question is 3 trinkets because 3*11 = 33 dollars is under the budget of $35. The amount left over is 35-33 = 2 dollars which is the remainder. It's not larger than 11, so we cannot buy any more trinkets at this point.
Answer:
10<em>m</em>
Step-by-step explanation:
Your teacher probably told you the necessary fundamentals of monomials. So, I'll just teach you the things needed for this particular question.
10<em>m</em>^3/(10<em>m</em>)(<em>m</em>)
First, in the denominator, since that <em>m</em> are being multiplied and they are the same <em>terms, </em>their exponents add:
10<em>m</em> * <em>m</em>
10<em>m</em>^1 * <em>m</em>^1
1 + 1 = 2
10<em>m</em>^2
Then, since that <em>m </em>are now being divided, their exponents subtract:
10<em>m</em>^3 / 10<em>m</em>^2
3 - 2 = 1
10<em>m</em>^1
10<em>m</em>
Answer:
Maybe in June? Mainly the government needs money to send out the security checks
Step-by-step explanation:
The slope of the line is 2/1 and the y-intercept is (0,-3). Using that information, we can figure out two points on the line.
Point 1: (0,-3)
Point 2: (1,-1)
For two triangles to be congruent by AAS:
1- Two angles in the first triangle must be equal to two angles in the second triangle
2- A non included side in the first triangle is equal to a non included side in the second triangle
Now, let's check our options. We will find that:
For the two triangles UTV and ABC:
angle T = angle A
angle V = angle C
TU (non-included between angles T & V) = AB (non-included between angles A & C)
Therefore, we can conclude that:
Triangles ABC and UTV are congruent by AAS
