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allochka39001 [22]
3 years ago
9

A horticulturist wants to improve the soil quality in a garden by adding 120 pounds of nitrogen and 54 pounds of potassium. A pa

ck of organic fertilizer contains 2 pounds of nitrogen and 3 pounds of potassium, and a pack of inorganic fertilizer contains 6 pounds of nitrogen and 2 pounds of potassium. How many packs of each type of fertilizer does the horticulturalist need to use? (Hint Write an equation for the total amount of nitrogen (120 pounds) obtained by adding the packs of both the fertilizers and another equation for the total amount of potassium (54 pounds) obtained by adding the packs of both the fertilizers.)
A organic fertilizer: 24 packs; inorganic fertilizer: 12 packs

B. organic fertilizer: 14 packs; inorganic fertilizer: 6 packs

C organic fertilizer: 15 packs; inorganic fertilizer: 8 packs

D. organic fertilizer: 9 packs; inorganic fertilizer: 17 packs

Е. organic fertilizer: 6 packs; inorganic fertilizer: 18 packs​
Mathematics
1 answer:
eimsori [14]3 years ago
6 0

x and y are the packs of organic and inorganic fertilizer, respectively.

pounds of nitrogen added = 2x + 6y = 120

pounds of potassium added = 3x + 2y = 54

eliminate the y terms. subtract the first equation from 3 times the second equation.

9x + 6y = 162

-2x - 6y = -120

------------------

7x = 42

x = 6

y = 18

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Answer:

8 feet

Step-by-step explanation:

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Now use similar triangles to write a proportion:

22 / (24 + x) = 5.5 / x

Cross multiply:

22x = 5.5 (24 + x)

Distribute:

22x = 132 + 5.5x

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16.5x = 132

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The shadow is 8 feet long.

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3 years ago
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3 years ago
A regular octagon is inscribed in a circle with a radius of 10 cm. What is the length of one side of the octagon?
Semenov [28]

Answer:

The length of one side of the octagon is 7.65 cm

Step-by-step explanation:

The parameters given are;

A regular octagon inscribed in a circle of radius, r, of 10 cm.

The length of each side is found from the isosceles triangle formed by the radius and one side of the octagon

The sum of interior angles in a polygon, ∑θ_i = 180 × (n - 2)

Where;

n = The number of sides of the polygon

θ_i = The interior angle of the polygon

For the octagon, we have;

n = 8, therefore;

∑θ_i = 180 × (8 - 2) = 1080

Given that there are eight equal angles in a regular octagon, we have;

∑θ_i = 8 × θ_i = 1080

θ_i = 1080/8 = 135°

The sum of angles at the center of the circle = 360

Therefore, the angle at the center (tip angle) of the isosceles triangle formed by the radius and one side of the octagon = 360/8 = 45°

The base angles of the isosceles triangle is therefore, (180 - 45)/2 = 67.5° = θ_i/2

The length of the base of the isosceles triangle formed by the radius and one side of the octagon = The length of one side of the octagon

From trigonometric ratios, the length of the base of the isosceles triangle is therefore;

2 × r × cos(θ_i/2) = 2×10 × cos(67.5°) = 7.65 cm

The length of the base of the isosceles triangle = 7.65 cm = The length of one side of the octagon.

7 0
3 years ago
Read 2 more answers
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maksim [4K]

Answer:

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Step-by-step explanation:

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hope this helps

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